Answer:
6*8=48 groups with elements of order 7
Step-by-step explanation:
For this case the first step is discompose the number 168 in factors like this:

And for this case we can use the Sylow theorems, given by:
Let G a group of order
where p is a prime number, with
and p not divide m then:
1) 
2) All sylow p subgroups are conjugate in G
3) Any p subgroup of G is contained in a Sylow p subgroup
4) n(G) =1 mod p
Using these theorems we can see that 7 = 1 (mod7)
By the theorem we can't have on one Sylow 7 subgroup so then we need to have 8 of them.
Every each 2 subgroups intersect in a subgroup with a order that divides 7. And analyzing the intersection we can see that we can have 6 of these subgroups.
So then based on the information we can have 6*8=48 groups with elements of order 7 in G of size 168
Domain from 1 to 6
Range from 1 to 4
Answer:
H 60
Step-by-step explanation:
You would need to find out what you would multiply times 0.5 to get 30. Then to get that answer just divide 30 by 0.5. which is 60
See the equation of future value of annuity ordinary through Google
Flao=4,770×(((1+0.055)^(34)−1)
÷(0.055))=448,747.87
Then
448,747.87−(448,747.87×0.15)
=381,435.69. 15% upon retirement.
Answer
54 students are in the science club
Step-by-step explanation:
84 divided by 2 = 42
42 + 12 =54
84 - 54 = 30
so the science club has 54 students and the robotics club has 30 students