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Lostsunrise [7]
3 years ago
14

Find the point on the line y = 2x +1 that is closest to the point (5, 2).

Mathematics
1 answer:
ELEN [110]3 years ago
7 0
I believe that it's (1,3) 
(tip: with these problems, try to use desmos.com)
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(52+2)-3x -6<br><br> help me with thanks
Yuri [45]

Answer:

48 - 3X

Step-by-step explanation:

( 52+2) - 3x - 6

54 - 3x - 6    So first we deal with the numbers in brackets and that is 52 + 2 giving us 54.

54 - 6 - 3x  Then you simplify the expression that is collecting like terms so then we subtract 6 from 54

48 - 3x This is the final expression after simplifying

HOPE THIS HELPED

3 0
2 years ago
Negative numbers that equal -60? (I need number that multiple That equal -60)
NikAS [45]

Answer:

-5 x -12

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Perform the indicated operations. Write the answer in standard form, a+bi.<br> 5-3i / -2-9i
Vsevolod [243]

\huge \boxed{\mathfrak{Answer} \downarrow}

\large \bf\frac { 5 - 3 i } { - 2 - 9 i } \\

Multiply both numerator and denominator of \sf \frac{5-3i}{-2-9i} \\ by the complex conjugate of the denominator, -2+9i.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2-9i\right)\left(-2+9i\right)})  \\

Multiplication can be transformed into difference of squares using the rule: \sf\left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2\right)^{2}-9^{2}i^{2}})  \\

By definition, i² is -1. Calculate the denominator.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{85})  \\

Multiply complex numbers 5-3i and -2+9i in the same way as you multiply binomials.

\large \bf \: Re(\frac{5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9i^{2}}{85})  \\

Do the multiplications in \sf5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9\left(-1\right).

\large \bf \: Re(\frac{-10+45i+6i+27}{85})  \\

Combine the real and imaginary parts in -10+45i+6i+27.

\large \bf \: Re(\frac{-10+27+\left(45+6\right)i}{85})  \\

Do the additions in \sf-10+27+\left(45+6\right)i.

\large \bf Re(\frac{17+51i}{85})  \\

Divide 17+51i by 85 to get \sf\frac{1}{5}+\frac{3}{5}i \\.

\large \bf \: Re(\frac{1}{5}+\frac{3}{5}i)  \\

The real part of \sf \frac{1}{5}+\frac{3}{5}i \\ is \sf \frac{1}{5} \\.

\large  \boxed{\bf\frac{1}{5} = 0.2} \\

3 0
2 years ago
If AC=5cm, BC=12cm, and m AC= 40 degrees what is the radius of the circumscribed circle
melamori03 [73]
Let's assume they meant C=40 degrees.  With an angle like that they're asking for approximation; we'll oblige.

The circumradius is the product of the triangle sides divided by four times the area.

Here we have remaining side given by the Law of Cosines.

AB^2 = AC^2 + BC^2 - 2\ AC \ BC \cos C

AB^2 = AC^2 + BC^2  - 2 AC \ AB \cos C = 5^2 + 12^2 - 2(5)(12) \cos 40^\circ

AB = \sqrt{  169 - 120 \cos 40 ^\circ}  \approx 8.77921789

The area is \frac 1 2\ AC \ BC \sin C = \frac 1 2 (5)(12) \sin 40^\circ \approx 19.283628



The circumradius is  r \approx \dfrac{(5)(12)(8.77921789 )}{ 4 (19.283628) }  = 6.829019329




5 0
3 years ago
<img src="https://tex.z-dn.net/?f=4%20%20%5Ccos%2860%20%2B%20%20%5Calpha%20%29%20%20%5Csin%2830%20%2B%20%20%5Calpha%20%29%20%20%
Yuri [45]

Answer:

i am very bad at o math i am only at 8 sorry

Step-by-step explanation:

if you could give me a brainliest.

5 0
2 years ago
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