Answer:

Step-by-step explanation:
This problem can be solved using the pythagorian theoreme:

Where:



We isolate our incognita an we get:

We supplant with the given data:





$63.09
She would have this amount
Answer:
21%
Step-by-step explanation:
the total number of students is 19.
the number of students that have an A is 7.
the number of students that have an A and are a boy is 3, which leaves 4 others in the category of getting an A.
4 out of the 19 total students could be female with an A.
4/19 = 0.21 = 21%
it is proven congreunt ASA axiom
<m=<m(given)A
MN=MN(common side)s
<o=<o(given)A