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Digiron [165]
3 years ago
8

Create an original rational function that has at least one asymptote (vertical, horizontal, and/or slant) and possibly a removab

le discontinuity. List these features of your function: asymptote(s) (vertical, horizontal, slant), removable discontinuity(ies), x-intercept(s), y-intercept, and end behavior.
Mathematics
1 answer:
Phoenix [80]3 years ago
3 0
<span>Since f has a vertical is at x = 2, then the denominator of the rational function contains the term (x - 2). Function f has the form. f(x) = g(x) / (x - 2) g(x) which is in the numerator must be of the same degree as the denominator since f has a horizontal asymptote. Also g(x) must contain the term (x + 5) since f has a zero at x = - 5. Hence f(x) = 3 (x + 5) / (x - 2)</span>
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lesantik [10]
For this Q:

mean=31
st.dev.=0.8
x=32

Calculate z-score:
z=(x-m)/s = (32-31)/0.8=1.25

This z-score value corresponding to the probability of 0.8944

<span />
6 0
3 years ago
20 POINTSSSS
marta [7]

Step-by-step explanation:

Commission earned

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A landscaper has enough cement to make a patio with an area of 150 Sq ft. The homeowner wants the length of the patio to be 6 ft
Natasha_Volkova [10]
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4 0
3 years ago
2x+2(1960/x)=200 please help for math hw
sp2606 [1]

Two solutions:

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3 0
3 years ago
A ball is thrown upward from the top of a 40 foot high building at a speed of 80 feet per second. The ball's height above
tekilochka [14]

it takes 5 seconds to reach a height of 40 ft. and It takes 2.5 seconds to reach maximum height.

Let h(t) represent the height of the ball at time t.

Given that the height is given by:

h(t) = -16t² + 80t + 40

1) For the ball to reach a height 0f 40 ft, h(t) = 40, hence:

40 = -16t² + 80t + 40

16t² - 80t = 0

t(t - 5) = 0

t = 0 or t = 5

Hence it takes 5 seconds to reach a height of 40 ft.

2) The maximum height is at h'(t) = 0,

h'(t) = -32t + 80

-32t + 80 = 0

32t = 80

t = 2.5

It takes 2.5 seconds to reach maximum height.

Find out more at: brainly.com/question/11535666

5 0
3 years ago
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