Answer:
15x^2-3x-1
Step-by-step explanation:
All we have to do is collect like terms and calculate! Hope this helps!
Answer:
Step-by-step explanation:
We first need to define a couple of variables. Let s = the cost of 1 squash and z = the cost of 1 zucchini.
Now lets translate the words into algebra:
"The cost of 5 squash and 2 zucchini is $1.32" ===> 5s + 2z = 1.32
"Three squash and 1 zucchini cost $0.75" ===> 3s + z = 0.75
There are several ways to solve systems of equations. Let's use substitution. We can find what z equals in terms of s by manipulating the second equation:
3s + z = 0.75
-3s -3s
------------ -------------
z = -3s +0.75
Now lets substitute (-3s + 0.75) into the first equation for z, then solve for s:
5s + 2(-3s + 0.75) = 1.32
Can you handle it from here?
(Hint: Once you have solved for s, you can substitute that value back into either of the equations and solve for z.)
Answer: C
Step-by-step explanation:
Answer:
Step-by-step explanation:
1) 4x -3
x = -7 ;
4x - 3 = 4*(-7) - 3 = - 28 - 3 = -31
x = 14 ;
4x - 3 = 4*14 - 3 = 56 - 3 = 53
x = 0
4x - 3 = 0 - 3 = -3
2) 6 -3x
x = -7 ;
6 - 3x = 6 - 3*(-7) = 6 + 21 = 27
x = 14
6 - 3x = 6 - 3*14 = 6 - 42 = -36
x = 0
6 - 3x = 6 - 0 = 6

4)
