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4 years ago

It takes 28 pounds of seed to completely plant a 5-acre field.

Mathematics

1 answer:

ycow [4]4 years ago

5 0

Answer:

5.6 pounds of seed per acre.

Step-by-step explanation:

It takes 28 pounds of seed to completely plant a 5-acre field.

For one acre it will take; $\frac{1}{5}$ × 28 pounds = 5.6 pounds of seed.

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(URGENT) need this for today!

Zigmanuir [339]

Answer:

right triangel

Step-by-step explanation:

the sides just add up to that i thinl

6 0

4 years ago

100 is 1/10 of what?

lawyer [7]

$\boxed{ \ 100 \ is \ \frac{1}{10} \ of \ 1,000 \ }$

<h3>Further explanation </h3>

The question can be rewritten to $\boxed{ \ 100 \ is \ \frac{1}{10} \ of \ M \ }$

This case about equations with one variable. We have to solve this calculation to obtain the value of M. Our task is to isolate the variable M alone at the end of the process on one side of the equation until the variable will be equal to a value on the opposing side.

Let's arrange it into an equation, i.e., $\boxed{ \ 100 \ = \ \frac{1}{10} \times \ M \ }$

Turn this equation over so that the position of variable M is on the left side.

$\boxed{ \ M \times \frac{1}{10} = 100 \ }$

Both sides are multiplied by 10 to isolate M on the left side. The fraction are eliminated.

$\boxed{ \ M \times \frac{1}{10} \times 10 = 100 \times 10 \ }$

M = 1,000

Therefore, we have calculated the number that was asked.

Hence $\boxed{ \ 100 \ is \ \frac{1}{10} \ of \ 1,000 \ }$

The significant thing to carry out is how to manipulate both sides of the equation with the algebraic properties of equality such as:

Adding
Subtracting
Multiplying, and/or
Dividing both sides of the equation with a similar number

And the commutative property of multiplication, i.e., $\boxed{ \ a \times b = b \times a \ }$

<h3>Learn more </h3>

The similar case brainly.com/question/106300
The similar case brainly.com/question/96882
Calculating mass based on density and volume brainly.com/question/4053884

Keywords: 100 is 1/10 of, solve, 1,000, variable, 2/7m - 1/7 = 3/14, algebraic properties of equality, one, linear equation, isolated, manipulate, operations, add, subtract, multiply, divide, fraction, equate, denominator, numerator, both sides, equal, the opposite, both sides are multiplied by, turn, calculation

7 0

3 years ago

Find the area of an isosceles trapezoid, if the lengths of its bases are 16 cm, and 30 cm, and the diagonals are perpendicular t

Klio2033 [76]

For this case we have:
a = 30 cm
c = 16 cm
We look for the length of the diagonal:
d = x + y
Where,
For x:
a ^ 2 = x ^ 2 + x ^ 2
x = a / root (2) = 30 / root (2) = 21.2132 cm
For y:
c ^ 2 = y ^ 2 + y ^ 2
y = c / root (2) = 16 / root (2) = 11.3137 cm
The diagonal is:
d = x + y
d = 21.2132 + 11.3137
d = 32.5269 cm
Then, the height is:
h = h1 + h2
For h1:
h1 = root (x ^ 2 - (a / 2) ^ 2) = root ((21.2132) ^ 2 - (30/2) ^ 2)
h1 = 15 cm
For h2:
h2 = root (y ^ 2 - (c / 2) ^ 2) = root ((11.3137) ^ 2 - (16/2) ^ 2)
h2 = 8 cm
Finally:
h = h1 + h2
h = 15 + 8
h = 23 cm
Then, the area is:
A = (1/2) * (a + c) * (h)
A = (1/2) * (30 + 16) * (23)
A = 529 cm ^ 2
Answer:
the area of an isosceles trapezoid is:
A = 529 cm ^ 2

4 0

3 years ago

Find The are of the shaded region

Vedmedyk [2.9K]

Answer:

the one you have highlighted is correct

Step-by-step explanation:

6 0

3 years ago

Tell whether the sequence is arithmetic. If it is, what is the common difference?

Lerok [7]

I think the answer is c