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alexdok [17]
3 years ago
13

In transaction (A) on 5/8, the cash account is an

Mathematics
1 answer:
Svet_ta [14]3 years ago
8 0
<span>In transaction (A) on 5/8, the cash account is a 2.
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Solve(x+y)^2=(x^2-2xy+y^2) and show your work
Shtirlitz [24]

(x + y)^2 = (x^2 - 2xy + y^2)

First distribute the ^2 on the left side of the equation to each term inside the parenthesis:

x^2+ 2xy + y^2

Now pick one of the variables to solve for and isolate it:

(solving for x)

x^2 + 2xy + y^2 = x^2 - 2xy + y^2

x^2+ 2xy = x^2 - 2xy

2xy = -2xy

-x = x

x = 0

When you solve for y in the equation it will turn out to be 0 as well

7 0
3 years ago
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The price of a shirt is 18.50, but you have a coupon that lowers the price by 20%. What is the price of the shirt after using th
AURORKA [14]
The new price of the shirt is $14.8
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3 years ago
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How to write a decimal as a fraction?
love history [14]

Answer:

Step-by-step explanation:

Convert Decimals to Fractions

Step 1: Write down the decimal divided by 1, like this: decimal 1.

Step 2: Multiply both top and bottom by 10 for every number after the decimal point. (For example, if there are two numbers after the decimal point, then use 100, if there are three then use 1000, etc.)

Step 3: Simplify (or reduce) the fraction.

5 0
2 years ago
What are the possible rational roots of the polynomial equation?<br><br> 0=2x7+3x5−9x2+6
RoseWind [281]

Answer: \pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}

Step-by-step explanation:

We can use the Rational Root Test.

Given a polynomial in the form:

a_nx^n +a_{n- 1}x^{n - 1} + … + a_1x^1 + a_0 = 0

Where:

- The coefficients are integers.

- a_n is the leading coeffcient (a_n\neq 0)

- a_0 is the constant term a_0\neq 0

Every rational root of the polynomial is in the form:

\frac{p}{q}=\frac{\pm(factors\ of\ a_0)}{\pm(factors\ of\ a_n)}

For the case of the given polynomial:

2x^7+3x^5-9x^2+6=0

We can observe that:

- Its constant term is 6, with factors 1, 2 and 3.

- Its leading coefficient is 2, with factors 1 and 2.

 Then, by Rational Roots Test we get the possible rational roots of this polynomial:

\frac{p}{q}=\frac{\pm(1,2,3,6)}{\pm(1,2)}=\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}

5 0
2 years ago
An apple has a mass of 0.25 kg. The apple is 3m high. What is the potential energy of the apple?
galben [10]

Answer:

Potential energy= mass x gravity x height

0.25x9.8x3=7.35 N

hope that answers your question

Step-by-step explanation:

5 0
3 years ago
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