-x² + 8x - 6 = 0
x = <u>-(8) +/- √((8)² - 4(-1)(-6))</u>
2(-1)
x = <u>-8 +/- √(64 - 20)</u>
-2
x = <u>-8 +/- √(44)
</u> -2<u>
</u>x = <u>-8 +/- 2√(11)
</u> -2
x = <u>-8 + 2√(11)</u> x = <u>-8 - 2√(11)
</u> -2 -2<u>
</u>x = 4 - √(11) x = -8 + √(11)
Answer:
y = 14
Step-by-step explanation:
move 5y over to the left and you should get -2y +6=-18. subtract 6from both sides and you will now have -2y=-24. divide bothe sides from -2 and you will get y=14
Answer:
No, it cannot have a unique solution. Because there are more variables than equations, there must be at least one free variable. If the linear system is consistent and there is at least one free variable, the solution set contains infinitely many solutions. If the linear system is inconsistent, there is no solution.
Step-by-step explanation:
the questionnaire options are incomplete, however the given option is correct
We mark this option as correct because in a linear system of equations there can be more than one solution, since the components of the equations, that is, the variables are multiple, leaving free variables which generates more alternative solutions, however when there is no consistency there will be no solution
Answer:
we need a picture...
Step-by-step explanation: