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irga5000 [103]
3 years ago
11

Monica built a porch that contained 2 different colors of bricks to create a neat pattern. She purchased the red bricks at $2 ea

ch and the gray bricks for $3 each. Write and solve a system of equations that could be used to
Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
4 0

Answer:

2x+3x=5x

Step-by-step explanation:

The reason for this answer is algebra. Since you give a full explanantion  on it I'm not sure if I answered it correctly. But here is what I think from what you gave of the question.  

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Is the equation below a function? explain<br>d) y2 = x2 + 5​
RoseWind [281]

Answer:

No

Step-by-step explanation:

y^2 = x^2 + 5​

Rewriting

y^2 - x^2 = 5

This is a hyperbola

We can use the vertical line test to show that it is not a function since a vertical line passes through more than one point.

5 0
3 years ago
Joan has a credit card that uses the previous balance method. The opening balance of one of her 30-day billing cycles was $6390,
Gekata [30.6K]

It would be something that looks like this:

((6390 * 0.17)/365) x 3


3 0
4 years ago
Read 2 more answers
A recipe that makes 7 servings calls for 1 1/6 cups of juice.
VMariaS [17]
1/7 cups per serving

6 0
3 years ago
Find the mean, variance &amp;a standard deviation of the binomial distribution with the given values of n and p.
MrMuchimi
A random variable following a binomial distribution over n trials with success probability p has PMF

f_X(x)=\dbinom nxp^x(1-p)^{n-x}

Because it's a proper probability distribution, you know that the sum of all the probabilities over the distribution's support must be 1, i.e.

\displaystyle\sum_xf_X(x)=\sum_{x=0}^n\binom nxp^x(1-p)^{n-x}=1

The mean is given by the expected value of the distribution,

\mathbb E(X)=\displaystyle\sum_xf_X(x)=\sum_{x=0}^nx\binom nxp^x(1-p)^{n-x}
\mathbb E(X)=\displaystyle\sum_{x=1}^nx\frac{n!}{x!(n-x)!}p^x(1-p)^{n-x}
\mathbb E(X)=\displaystyle\sum_{x=1}^n\frac{n!}{(x-1)!(n-x)!}p^x(1-p)^{n-x}
\mathbb E(X)=\displaystyle np\sum_{x=1}^n\frac{(n-1)!}{(x-1)!((n-1)-(x-1))!}p^{x-1}(1-p)^{(n-1)-(x-1)}
\mathbb E(X)=\displaystyle np\sum_{x=0}^n\frac{(n-1)!}{x!((n-1)-x)!}p^x(1-p)^{(n-1)-x}
\mathbb E(X)=\displaystyle np\sum_{x=0}^n\binom{n-1}xp^x(1-p)^{(n-1)-x}
\mathbb E(X)=\displaystyle np\sum_{x=0}^{n-1}\binom{n-1}xp^x(1-p)^{(n-1)-x}

The remaining sum has a summand which is the PMF of yet another binomial distribution with n-1 trials and the same success probability, so the sum is 1 and you're left with

\mathbb E(x)=np=126\times0.27=34.02

You can similarly derive the variance by computing \mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2, but I'll leave that as an exercise for you. You would find that \mathbb V(X)=np(1-p), so the variance here would be

\mathbb V(X)=125\times0.27\times0.73=24.8346

The standard deviation is just the square root of the variance, which is

\sqrt{\mathbb V(X)}=\sqrt{24.3846}\approx4.9834
7 0
3 years ago
Grace starts with 100 milligrams of a radioactive substance. The amount of the substance decreases by 14 each week for a number
Eva8 [605]

Answer:

I Believe Grace Is Dead Dreamer?!

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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