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Setler79 [48]
3 years ago
11

If twice a number is subtracted from 11, the result is 4 more than the number. What is the number?

Mathematics
1 answer:
Flauer [41]3 years ago
4 0

Let the number = x.

So 2 times x subtracted from 11 is written as 11-2x

The result is 4 more than the number is written as 4 +x

Now you have 11-2x = 4 + x

We can now solve for x.

Add 2x to each side:

11 = 4 + 3x

Subtract 4 from each side:

7 = 3x

Divide both sides by 3:

x = 7/3

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3y + 3

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2 years ago
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5 0
3 years ago
If f(x)= 6x+7, determine the value of f(r-2)
Tanzania [10]

The value of f(r - 2) is 6r - 5

<h3>What is a function?</h3>

Function can be defined as an expression, rule, or law that defines a relationship between one variable known as the independent variable and another called the dependent variable.

From the information given ,we have;

f(x)= 6x+7, with f ( r - 2)

From here, we have that x = r -2

Now, let's substitute x as r - 2 in the function given;

f(x) = 6x + 7

f(r - 2) = 6 ( r - 2) + 7

Expand the bracket

f(r - 2) = 6r - 12 + 7

collect like terms

f(r - 2) = 6r - 5

Thus, the value of f(r - 2) is 6r - 5

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5 0
2 years ago
Which function could be a stretch of the exponential decay function shown on the graph?
dezoksy [38]

Answer:

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Step-by-step explanation:

The given options are,

a) f(x) = 2^{(6x)}

b) f(x) = (\frac {1}{2})^{(6x)}

c) f(x) = 2 \times (\frac {1}{6})^{x}

d) f(x) = \frac {1}{2} \times (\frac {1}{6})^{x}

Now, clearly a) is a monotonically increasing function, hence discarded, and both of c)  and d) don't pass through (0, 1) hence they are also discarded.

Only b) is a decay function which does also pass through (0, 1), hence, b) is the correct option.

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