Answer: he invested $46062.5 at 6% and $23031.25 at 10%
Step-by-step explanation:
Let x represent the amount which he invested in the account paying 6% interest.
Let y represent the amount which he invested in the account paying 10% interest.
He puts twice as much in the lower-yielding account because it is less risky.. This means that
x = 2y
The formula for determining simple interest is expressed as
I = PRT/100
Considering the account paying 6% interest,
P = $x
T = 1 year
R = 6℅
I = (x × 6 × 1)/100 = 0.06x
Considering the account paying 10% interest,
P = $y
T = 1 year
R = 10℅
I = (y × 10 × 1)/100 = 0.1y
His annual interest is $7370dollars. it means that
0.06x + 0.2y = 7370 - - - - - - - - - -1
Substituting x = 2y into equation 1, it becomes
0.06 × 2y + 0.2y = 7370
0.12y + 0.2y = 7370
0.32y = 7370
y = 7370/0.32
y = $23031.25
x = 2 × 23031.25
x = 46062.5
I'm not going to do the entire question, but I'll do the first part.
For the first part, you have to set up an inequality. Use context clues, such as
no more than (the one used in this sentence) to figure out what the symbol should be for the inequality.
In this case, because it is NO MORE THAN 6400, it would be:
6400

250r + 475p
where r represents the # refrigerators, and p represents the # pianos
Now that you have the equation, make the graph, then for the 3rd part, plug in 12 and 8 to r and p to see if it keeps the inequality true.
Hope this helps! :)
Sorry don’t know! Hope u find someone that does know
Answer:
Kabuls = 7.5
Carumpts= 0.85
Step-by-step explanation:
Let x represent the price of kabuls
Let y represent the price of carumpts
8x + 2y= 61.70......equation 1
3x + 10y= 31.........equation 2
Multiply equation 1 by 3 and equation 2 by 8
24x + 6y= 185.1
24x + 80y= 248
-74y = -62.9
y= 62.9/74
y= 0.85
Substitute 0.85 for y in equation 1
8x + 2(0.85) = 61.70
8x + 1.7= 61.70
8x = 61.70-1.7
8x = 60
x= 60/8
x= 7.5
Hence the dollar value for kabuls is 7.5 and carumpts is 0.85