Answer: Percentage decrease = 20% × 7,720
New value = 7,720 - Percentage decreaseNew value =
7,720 - Percentage decrease =
7,720 - (20% × 7,720) =
7,720 - 20% × 7,720 =
(1 - 20%) × 7,720 =
(100% - 20%) × 7,720 =
80% × 7,720 =
80 ÷ 100 × 7,720 =
80 × 7,720 ÷ 100 =
617,600 ÷ 100 =
6,176
New value - 7,720 =
6,176 - 7,720 =
- 1,544
Step-by-step explanation:
First you take all the scores he got and put them into a problem. Next you add all the scores that Cameron got. He needs to get 15 over par to get his best score.
<span>1) 5+(-15)-30 </span>
<span>2) -12-3+15 </span>
<span>3) -50+(25)-10 </span>
Examples:
<span>How to do it </span>
<span>Hint- use kco </span>
<span>10-12+25-(50)</span>
volume = l x w x h
51 x 44 x 8 = 17952 cubic feet
1 cubic foot = 0.0283168 cubic meters
17952 x 0.0283168 = 508.343 cubic meters
1 cubic meter = 1,000,000 cubic centimeters
508.343 x 1000000 = 508,343,000 cubic centimeters
Answer:
<h3>-6</h3>
Step-by-step explanation:
Let the slope of the first line be m1
Let the slope of the second line be m2
If both lines are perpendicular, then;
m1m2 = -1
Get m1, the slope of the line passing through A (-2, 0) and B (2,-k).
m1 = y2-y1/x2-x1
m1 = -k-0/2-(-2)
m1 = -k/4
Get the slope of the line 3y + 2x = 5
Rewrite the equation;
3y = -2x + 5
y = -2/3 x + 5/3
Hence the slope of the line m2 is -2/3
Since m1m2 = -1, then;
-k/4(-2/3) = -1
2k/12 = -1
k/6 = -1
k = -6
Hence the value of k is -6
y = slope (x) + y - intercept
To find the slope we need to find out how much the x's and y's increase or decrease...
To find the y - intercept if any, simply look for coordinates ( 0 , y ) or 0 and a #.
~~
In this case, as time passes, the water level decreases therefore we have a negative slope.
Time is our x and amount (ft) is our y.
On the x side it increases by 2
On the y side it decreases by 10
Now do y over x ==> 10 over 2 and get 5 ==> m
-5 is our slope and 50 is our y - intercept
~~
The "rate of change" is another word for slope.
Well, slope is - 5ft is our slope.
~~
I hope that helps you out!!
Any more questions, please feel free to ask me and I will gladly help you out!!
~Zoey