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2 years ago

Can someone explain this to me?

Mathematics

1 answer:

Evgesh-ka [11]2 years ago

3 0

The slope of Line M (y = 2/3x - 3) is 2/3. To figure out the slope of Line N, you need to use the equation:
$m = \frac{y_2-y_1}{x_2-x_1}$

Choose any two points on the table, I chose (-2, -2) and (4, 2). Plug in and solve:
$m = \frac{2-(-2)}{4-(-2)} = \frac{2+2}{4+2} = \frac{4}{6} = \frac{2}{3}$

So, they do indeed have the same slope of 2/3. Therefore, the answer must be A.

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How many students got eight or more answers correct?

slamgirl [31]

Answer:

Step-by-step explanation:

You have to count the number of dots there are after the number 8. (This includes the dotes above 8.)

7 0

3 years ago

Read 2 more answers

The leopard population in an African wildlife area is currently 17. Due to a new conservation effort, conservationists hope the

kykrilka [37]

Answer:

$a{_n} = 17 + (n - 1)4$ for n = 1, 2, . . . , 20.

Step-by-step explanation:

This is an arithmetic sequence, because the population is said to increase by 4 animals yearly. The formula for the nth term in an arithmetic sequence is given by:

$a{_n} = a{_1} + (n - 1)d$ where $a_n$ is the nth term, [/tex]a_1[/tex] is the first term, n = 1, 2, . . . and d is the common difference.

Since they are currently 17, this implies that the first number in the population sequence will be 17. In order words, the first term is 17.

Since they increase by 4 yearly, then the common difference is 4.

Since it's for 20years, the n = 1, 2, . . ., 20. The explicit formula is therefore:

$a{_n} = 17 + (n - 1)4$ for n = 1, 2, . . . , 20.

8 0

2 years ago

in a random sample of 200 people, 154 said that they watched educational television. fine the 90% confidence interval of the tru

melisa1 [442]

Answer:

[0.7210,0.8189] = [72.10%, 81.89%]

Step-by-step explanation:

The sample size is

n = 200

the proportion is

p = 154/200 = 0.77

Since both np ≥ 10 and n(1-p) ≥ 10

We can approximate this discrete binomial distribution with the continuous Normal distribution. As the sample size is large enough, not applying the continuity correction factor makes no significant difference.

The approximation would be to a Normal curve with this parameters:

Mean

p = 0.77

Standard deviation

$\bf s=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.77*0.23}{200}}=0.0298$

The 90% confidence interval for the proportion would be then

$\bf [0.77-z^*0.0298, 0.77+z^*0.0298]$

where $\bf z^*$ is the 10% critical value for the Normal N(0,1) distribution , this is a value such that the area under the N(0,1) curve outside the interval $\bf [-z^*,z^*]$ is 10%=0.1