Answer:
-1, 4+i, 4-i
Step-by-step explanation:
x^4- 6x^3 + 2x^2 + 26x + 17
Using the rational root theorem
we see if 1, -1, -17 or 17 are roots
Check and see if 1 is a root
1^4- 6(1^3) + 2(1^2) + 26(1) + 17=0
1-6+2+26+17 does not equal 0 1 is not a root
-1
1^4- 6(-1^3) + 2(1^2) + 26(-1) + 17=0
1 +6 +2 -26+17 = 0
-1 is a root
Factor out (x+1)
(x+1) ( x^3-7x^2+9x+17)
Using the rational root theorem again on x^3-7x^2+9x+17
Checking -1
-1 -7 -9 +17=0
-1 is a root
(x+1) (x+1) (x^2-8x+17)
Using the quadratic on the last
8 ±sqrt(8^2 - 4(1)17)
--------------------------------
2
gives imaginary roots
4±i
Answer:
A. A horizontal shift to the right 7.5 units
Step-by-step explanation:
Replacing x with x-7.5 shifts the graph 7.5 units to the <em>right</em>.
__
In general, g(x) = f(x-h)+k will shift h units right and k units up. In this problem there is no vertical shift.
Hi friend,
Converting mixed numbers to fractions<span>, our initial equation becomes,
</span>
11/4 x 11/6
Applying the fractions formula for multiplication<span>,
</span>
11 x 11 --> 121
-----
4 x 6 ------> 24
Simplifying 121/24<span>, the answer is:</span>
5 1/24
Hope this helped
