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3 years ago

What is the difference between the smallest six digit number and the greatest four digit number

2 answers:

7 0

Working with whole numbers only ... the smallest 6-digit number is 100,000, the greatest 4-digit one is 9,999, and their difference is 90,001 .

drek231 [11]3 years ago

6 0

The smallest (whole number ) 6 digit number is 1,000,000
The greatest (whole number 4 digit number is 9,999
The difference between them means to subtract the four digit number from the 6 digit number.
The difference is 990,001

I would not consider 000001 to be a 6 digit number (in case this is supposed to be a trick question.)

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quester [9]

Step-by-step explanation:

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x = √136

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3 years ago

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Sloan [31]

Step-by-step explanation:

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3 years ago

What number is to be multiplied with 1/3 to get 1/21

dybincka [34]

Answer:

1/7

Step-by-step explanation:

Since we do not know the number let us use the alphabet A to represent the unknown number

A × 1/3= 1/21

A/3= 1/21

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2 years ago

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for v= 4i - 5j, find unit vector u in the direction of v, and write your answer as a linear combination of the standard unit vec

umka21 [38]

Answer:

a. $u=\frac{4\sqrt{41}i }{41}-\frac{5\sqrt{41}j}{41}$

Step-by-step explanation:

The given vector is v= 4i - 5j

The magnitude of this vector is;

$|v|=\sqrt{(-4)^2+(-5)^2}$

$|v|=\sqrt{16+25}$

$|v|=\sqrt{41}$

The unit vector u in the direction of v is;

$u=\frac{v}{|v|}$

$u=\frac{4i - 5j}{\sqrt{41}}$

$u=\frac{4i }{\sqrt{41}}-\frac{5j}{\sqrt{41}}$

We rationalize to get

$u=\frac{4\sqrt{41}i }{41}-\frac{5\sqrt{41}j}{41}$

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3 years ago

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a floor is 450 ft by 90 ft. A scale drawing of the floor on grid paper uses a scale of 1 unit:5 feet. what are the dimensions of

Minchanka [31]

450/5= 90 units

90/5= 18 units

All you need to do is divide the real dimensions by the scale dimensions, and turn that answer to units. Notice: It said 1 unit: 5 feet

The scale drawing was 90 to 18 units.

I hope this helps!
~kaikers

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2 years ago