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3 years ago

Find the prime factorization of 24

Mathematics

2 answers:

scZoUnD [109]3 years ago

4 0

Answer:

2,2,2,3

Step-by-step explanation:

2*2*2*3=24

MrRissso [65]3 years ago

3 0

The prime factor is 2 x 2 x 2 x 3

You have to break down everything first into 2 factors. 24= 2 x 12.

2 is the the prime number____________________________^^^

12 is the composite can be broken down_____I>3 x 4

3 is the prime number

4 is the composite so it can be broken down ______ 2 x 2.

Have a good day-Uni

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john's commute time to work during the week follows the normal probability distribution with a mean time of 26.7 minutes and a

Angelina_Jolie [31]

To evaluate the probability that a randomly selected day will be between 28 and 34 minutes we proceed as follows:
P(28<x<34)
First we evaluate the z-score for the above values:
z=(x-σ)/μ
μ=26.7
σ=5.1

when:
x=28
z=(28-26.7)/5.1
z=0.26
P(z<0.26)=0.6026

when x=34
z=(34-26.7)/5.1
z=1.43
P(z<1.43)=0.9236
hence:
P(28<x<34)=0.9236-0.6026=0.321~32.1%

6 0

3 years ago

15 r minus 6 r = 36. What is the value of r?

vodomira [7]

Answer:

r=4

Step-by-step explanation:

15r-6r=36

9r=36

r=36/9

r=4

3 0

3 years ago

Read 2 more answers

the cost of renting a scooter is represented by 3j+5. Write and simplify an expression that represents the cost of renting 6 sco

wariber [46]

Simplified expression that represents the cost of renting 6 scooters is 18 j +30

<u>Step-by-step explanation:</u>

Given data:

The cost of renting of a scooter is represented by 3j +5

So, from that, we can say in general,

The cost of renting of n scooters is represented by

$n \times(3 j+5)$

But according to given, the value of n is 6. i.e. to find the cost for six number of scooters. We can calculate now as follows

So, the cost of renting of a scooter is represented by

$6 \times(3 j+5)=18 j+30$

3 0

3 years ago

A college student is taking two courses. The probability she passes the first course is 0.73. The probability she passes the sec

zhenek [66]

Answer:

b) No, it's not independent.

c) 0.02

d) 0.59

e) 0.57

f) 0.5616

Step-by-step explanation:

To answer this problem, a Venn diagram should be useful. The diagram with the information of Event 1 and Event 2 is shown below (I already added the information for the intersection but we're going to see how to get that information in the b) part of the problem)

Let's call A the event that she passes the first course, then P(A)=.73

Let's call B the event that she passes the second course, then P(B)=.66

Then P(A∪B) is the probability that she passes the first or the second course (at least one of them) is the given probability. P(A∪B)=.98

b) Is the event she passes one course independent of the event that she passes the other course?

Two events are independent when P(A∩B) = P(A) * P(B)

So far, we don't know P(A∩B), but we do know that for all events, the next formula is true:

P(A∪B) = P(A) + P(B) - P(A∩B)

We are going to solve for P (A∩B)

.98 = .73 + .66 - P(A∩B)

P(A∩B) =.73 + .66 - .98

P(A∩B) = .41

Now we will see if the formula for independent events is true

P(A∩B) = P(A) x P(B)

.41 = .73 x .66

.41 ≠.4818

Therefore, these two events are not independent.

c) The probability she does not pass either course, is 1 - the probability that she passes either one of the courses (P(A∪B) = .98)

1 - P(A∪B) = 1 - .98 = .02

d) The probability she doesn't pass both courses is 1 - the probability that she passes both of the courses P(A∩B)

1 - P(A∩B) = 1 -.41 = .59

e) The probability she passes exactly one course would be the probability that she passes either course minus the probability that she passes both courses.

P(A∪B) - P(A∩B) = .98 - .41 = .57

f) Given that she passes the first course, the probability she passes the second would be a conditional probability P(B|A)

P(B|A) = P(A∩B) / P(A)

P(B|A) = .41 / .73 = .5616

4 0

4 years ago

Plz help and answer all questions thx

ElenaW [278]

I know b is James, Olivia, Feng, Carmela

7 0

4 years ago