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Dennis_Churaev [7]
3 years ago
13

How is using the Pythagorean theorem in a rectangular prism similar to using it in a rectangle

Mathematics
1 answer:
kykrilka [37]3 years ago
5 0

Answer:

ok

Step-by-step explanation:

well first off a rectangle does not have a diameter...  

it has a width and a length  

u could use pythag to solve for a side of the rectangle, given that there is also a triangle inscribed into the rectangle  

lets say ur given the width of a rectangle and u have to solve for the length  

u are also given the diagonal which stretches from one corner to the other forming a triangle with the width and length of the rectangle  

say the diagonal was 5cm long and the width was 3cm long, and u have to find the length, x  

5^2 = 3^2 + x^2  

25 = 9 + x^2  

x^2 = 16  

x=4

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Determine the value of x. : A) B) 4 C) 4 D) 8
likoan [24]
The hypotenuse is always the longest side of a triangle and seeing that it is 8, X has to be something smaller so X is likely 4.
3 0
2 years ago
I got 150.8 so what answer should I put if this is right.
marusya05 [52]

Answer:

Yes its around 150.8 so your right but you rounded up so you have to round down to 150.72

Step-by-step explanation:

3 0
3 years ago
Suppose that you are to make a rectangular box with a square base from two different materials. The material for the top and fou
saw5 [17]

Answer:

height = 14.5 ft

width = length = 3.2 ft

Step-by-step explanation:

Let the side of the square base is a and the height of the box is h.

The material required to make the box is equal to the total surface area of the box.

Area of base = a²

Cost of square base is $ 2 per ft²

So, the cost of making base = 2a²

Area of four walls + area of top = 2 (a² + ah + ah) + a² =  3a² + 2ah

Cost of making walls and the top is $ 1 per ft²

So, the cost of making walls and the top = 1 x ( 3a² + 2ah)

Total cost of making the box = 2a² + 3a² + 2ah = 5a² + 2ah

According to the question

144 = 5a² + 2ah

h = \frac{144-5a^{2}}{2a}     .... (1)

The volume of the box is V = length x width x height

V = a x a x h

V = 72 a - 2.5 a³     from equation (1)

Differentiate both sides with respect to a.

dV/da = 72 - 7.5 a²

Put, it equal to zero for maxima and minima

7.5 a² = 72

a = 3.2 ft

Put in equation (1)

h = \frac{144-5\times 3.2\times 3.2}{2\times 3.2}

h = 14.5 ft

So, the dimensions of the box are

height = 14.5 ft

width = length = 3.2 ft

6 0
3 years ago
3/4 divided by 5 PLEASE HELP ME
mylen [45]

3/4 x 5 = 3.75

Hope this helps!

5 0
4 years ago
Evaluate: 5/8 - (1/4)²
Viefleur [7K]

Answer:

5/8 - (1/4)^2 = 0.5625, hope this helps!

6 0
3 years ago
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