We know that the right triangle has one 90 degree angle and two acute (< 90 degree) angles. Since the sum of the angles of a triangle is always 180 degrees.
<u>To find x:</u>
(10x - 20) + (6x + 8) = 180
16x - 12 = 180
+12 +12
16x = 192
----- -----
16 16
x = 12
<u>Check:</u>
(10(12) - 20) + (6(12) + 8) = 180
(120 - 20) + (72 + 8) = 180
100 + 80 = 180
180 = 180
<u>Angle (10x - 20):</u>
(10(12) - 20)
(120 - 20)
100
<u>Angle (6x + 8):</u>
(6(12) + 8)
(72 + 8)
80
Answer:
m≥3
Step-by-step explanation:
Answer: 8,762.1 . The nearest tenth of a pound should be 2, the decimal throwing me off
I have to say something bc I am sleepy
Answer:
Approximately mMK is 53 degrees
Step-by-step explanation:
Here, we want to find the length of MK
As we can see, we have a right triangle at LNK
so
let us find the angle at L first
9 is adjacent to the angle at L and also, 15 is the hypotenuse of the angle at L
so the trigonometric identity that connects adjacent to the hypotenuse is the cosine
It is the ratio of the adjacent to the hypotenuse
So;
cos L = 9/15
L = arc cos (9/15)
L = 53.13 degree
Approximately, L = 53 degrees
so now, we want to get the arc length MK
We are to use the angle-arc relationship here
Using this; arc length MK is equal to the measure of L at the center which is 53 degrees
