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Lorico [155]
3 years ago
8

Which pairs of triangles must be similar? Bottom question

Mathematics
1 answer:
BaLLatris [955]3 years ago
7 0

which pairs of the triangle must be similar the answer is b

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I NEED HELP PLZ ASAP , I AM SO STUCK ON THIS.
Bezzdna [24]

Function

d. 4f(t)

=4(t²+9)

=4t²+36

e. (f(t))²+8

=(t²+9)² + 8

= t⁴+18t²+81+8

= t⁴+18t²+89

5 0
2 years ago
it took Simon 33 minutes to run 5.5 miles. did he run faster or slower than 1 mile every 5 minutes how can you tell ​
vitfil [10]
Simon ran slower than 1 mile every 5 minutes.

Because 33 / 5.5 = 6. So he ran 1 mile every 6 minutes, not 5.
4 0
3 years ago
What is the product of z1 and z2 if
MaRussiya [10]

Answer:

308[cos(45) + isin(45)]

Step-by-step explanation:

z1×z2:

Modulus: r1 × r2

= 7×44 = 308

Argument: theta1 + theta2

= -70 + 115 = 45

z1z2 = 308[cos(45) + isin(45)]

Or

z1z2 = 154sqrt(2) + (i)154sqrt(2)

sqrt: square root

8 0
3 years ago
Arthur has a balance of $2330 on his credit card, which he plans to pay off by
docker41 [41]

Answer:

$80

Step-by-step explanation:

A P E X

5 0
3 years ago
Circle A is shown. Secant W Y intersects tangent Z Y at point Y outside of the circle. Secant W Y intersects circle A at point X
timama [110]

Circle A is missing, so i have attached it.

Answer:

∠XYZ = 35°

Step-by-step explanation:

We want to find the angle ∠XYZ in the image attached.

To solve that, we will use the formula in the theorem for angle formed by secants or tangents. Thus;

∠XYZ = ½(arc WZ - arc XZ)

From the image, arc WZ = 175° and arc XZ = 105°

Thus;

∠XYZ = ½(175 - 105)

∠XYZ = ½(70)

∠XYZ = 35°

5 0
3 years ago
Read 2 more answers
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