Question

Find the slope of the line that passes through (3, 7) and (6, 8).

Answer 1

Answer:

Slope = 1/3

Step-by-step explanation:

Step 1: Define general form of equation of line

An equation of a straight line on two-dimensional plane could be represented in form of: y = Mx + b, with M is slope and b is y-intercept

Step 2: Set up the system to solve for slope M of equation of line

That equation passes 2 points, which are represented in form of (x, y), (3, 7) and (6, 8).

Substitute these values of x and y into the original equation in step 1:

7 = 3M + b

8 = 6M + b

Step 3: Solve the system of equations in step 2 for M

Subtract 1st equation from 2nd equation:

8 - 7 = 6M - 3M + b - b

Simplify both sides:

1 = 3M

Divide both sides by 3:

=> M = 1/3

Hope this helps!

:)

Answer 2

Answer:

$slope = \frac{1}{3}$

Step-by-step explanation:

$(3 \: \: \: ,\: \: \: 7) = > (x1 \: \: \: ,\: \: \: x2) \\ (6 \: \: \: ,\: \: \: 8) = > (y1 \: \: \: \: , \: \: \: y2)$

$slope \\ = \frac{y1 - y2}{x1 - x2} \\ = \frac{7 - 8}{3 - 6} \\ = \frac{ - 1}{ - 3} \\ = \frac{1}{3}$

hope this helps

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