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3 years ago

Find the equation of the line for each situation.

Mathematics

1 answer:

Flauer [41]3 years ago

7 0

Step-by-step explanation:

1) y = -x+4

2) y-4= -2(x-3)

y = -2x+6+4

y = -2x+10

3) slope = (3+1)/(9-1) = 4/8=½

the Equation =>

y+1= ½(x-1)

y = ½x -½-1

y = ½x - 1½ or 2y = x -3

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I need help ASAP please

Lorico [155]

Volume of a right hexagonal pyramidd is $\frac{ \sqrt{3} }{2}a^{2}h$ where a is the base side legnth and h=height
side legnth=12
height=36
subsitute
V= $\frac{ \sqrt{3} }{2}(12^{2}) (36)$
V= $\frac{ \sqrt{3} }{2} (144)(36)$
V= $\frac{ \sqrt{3} }{2} (5184)$
V= $\frac{ 5184 \sqrt{3} }{2}$
V= $2592 \sqrt{3}$
V=4489.48 cm^3

6 0

3 years ago

Help meee!!<br> pleaseee

uysha [10]

Answer:

5^9 is not a square number

Step-by-step explanation:

5^9 is not a square number because it is not 5^2, or a multiple of itself. 4^2 is a square number. 4x4=16. 5x5 definitely does not equal 1953125!

3 0

3 years ago

Jivesh also has a more powerful Model B rocket. For this rocket, he uses the equation h=-490t^2+1260t. When is the height of the

kkurt [141]

Answer:

1.29 s

Step-by-step explanation:

h = -490t² + 1260t

810 = -490t² + 1260t

490t² - 1260t + 810 = 0

49t² - 126t + 81 = 0

(7t - 9)² = 0

7t - 9 = 0

t = 9/7

t ≈ 1.29

4 0

3 years ago

9) Find the equation of a mirror line to the points Q (1,2) and Q1 (-1,2)<br><br>

Harman [31]

Answer:

x = 0

Step-by-step explanation:

Q(1, 2 ) and Q1(- 1, 2 ) are both 1 unit from the y- axis

Q is 1 unit to the right of the y- axis and Q1 is 1 unit is 1 unit to the left of the y-axis, thus

The y- axis is the mirror line with equation x = 0

8 0

4 years ago

C is inversely operational to d when c=3 , d=8 express c in terms of d

Vinvika [58]

Answer:

the answer is C=3 and D=8

Step-by-step explanation:

hope i helped you

7 0

2 years ago