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Marrrta [24]
3 years ago
10

Using the quadratic formula to solve 2x^2 = 4x – 7, what are the values of x?

Mathematics
2 answers:
LekaFEV [45]3 years ago
3 0

For this case we have the following quadratic equation:

2x ^ 2 = 4x - 7

Rewriting the equation we have:

2x ^ 2 - 4x + 7 = 0

From here, we have:

a=2 b = -4c = 7

Substituting values in the quadratic equation we have:

x = \frac{-b+/-\sqrt{b^2-4ac}}{2a}

x = \frac{-(-4)+/-\sqrt{(-4)^2-4(2)(7)}}{2(2)}

Rewriting the equation we have:

x = \frac{4+/-\sqrt{16-56}}{4}

x = \frac{4+/-\sqrt{-40}}{4}

x = \frac{4+/-\sqrt{-4*10}}{4}

x = \frac{4+/-2i\sqrt{*10}}{4}

x = \frac{2+/-i\sqrt{*10}}{2}

Answer:

The values of x are given by:

x = \frac{2+i\sqrt{*10}}{2}

x = \frac{2-i\sqrt{*10}}{2}

MAVERICK [17]3 years ago
3 0

Answer:

Is C.

Ccccccccccccccc

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Step-by-step explanation:

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