Question

Using the quadratic formula to solve 2x^2 = 4x – 7, what are the values of x?

Answer 1

For this case we have the following quadratic equation:

$2x ^ 2 = 4x - 7$

Rewriting the equation we have:

$2x ^ 2 - 4x + 7 = 0$

From here, we have:

$a=2 b = -4c = 7$

Substituting values in the quadratic equation we have:

$x = \frac{-b+/-\sqrt{b^2-4ac}}{2a}$

$x = \frac{-(-4)+/-\sqrt{(-4)^2-4(2)(7)}}{2(2)}$

Rewriting the equation we have:

$x = \frac{4+/-\sqrt{16-56}}{4}$

$x = \frac{4+/-\sqrt{-40}}{4}$

$x = \frac{4+/-\sqrt{-4*10}}{4}$

$x = \frac{4+/-2i\sqrt{*10}}{4}$

$x = \frac{2+/-i\sqrt{*10}}{2}$

Answer:

The values of x are given by:

$x = \frac{2+i\sqrt{*10}}{2}$

$x = \frac{2-i\sqrt{*10}}{2}$

Answer 2

Answer:

Is C.

Ccccccccccccccc