All categories

3 years ago

Evaluate the exponential function A(t) = 150(1.05)7 to the nearest hundredth.

Mathematics

2 answers:

andrey2020 [161]3 years ago

6 0

Answer:

We have 150(1.05)⁷ = 211.07

Step-by-step explanation:

We need to find the value of A(t) = 150(1.05)⁷ to the nearest hundredth.

A(t) = 150(1.05)⁷ = 211.0650634

Rounding the value in to nearest hundredth

150(1.05)⁷ = 211.0650634 = 211.07

So we have 150(1.05)⁷ = 211.07

Amiraneli [1.4K]3 years ago

4 0

Nearest hundredth means the second decimal digit.

$150( {1.05}^{7} ) = 211.065$

Notice that the third digit is 5 so the second digit rounds to 7.

$= 211.07$

Hope that helps you :)

You might be interested in

What are x and 8 in this lineat equation? 8/x+5=50/25

MatroZZZ [7]

Answer:

x= -8/3

Step-by-step explanation:

4 0

3 years ago

30 points!!<br> What is the sum of the first six terms of the series?<br> 48 - 12 + 3 - 0.75 +...

Lunna [17]

Answer:

The sum of the first six terms is 38.39

Step-by-step explanation:

This is a geometric sequence since the common difference between each term is $-\frac{1}{4}$

Thus, $r=-\frac{1}{4}$

To find the sum of first six terms, we need to find the fifth and sixth term of the sequence.

To find the fifth term:

The general form of geometric sequence is $a_{n}=a_{1} \cdot r^{n-1}$

To find the fifth term, substitute $n=5$ in $a_{n}=a_{1} \cdot r^{n-1}$

$\begin{aligned}a_{5} &=(48) \cdot\left(-\frac{1}{4}\right)^{5-1} \\&=(48) \cdot\left(-\frac{1}{4}\right)^{4} \\&=(48)\left(\frac{1}{256}\right) \\a_{5} &=0.1875\end{aligned}$

To find the sixth term, substitute $n=6$ in $a_{n}=a_{1} \cdot r^{n-1}$

$\begin{aligned}a_{6} &=(48) \cdot\left(-\frac{1}{4}\right)^{6-1} \\&=(48) \cdot\left(-\frac{1}{4}\right)^{5} \\&=(48)\left(-\frac{1}{1024}\right) \\a_{5} &=-0.046875\end{aligned}$

To find the sum of the first six terms:

The general formula to find Sn for $|r|$ is $S_{n}=\frac{a\left(1-r^{n}\right)}{1-r}$

$\begin{aligned}S_{6} &=\frac{48\left(1-\left(-\frac{1}{4}\right)^{6}\right)}{1-\left(-\frac{1}{4}\right)} \\&=\frac{48\left(1-\frac{1}{4096}\right)}{1+\frac{1}{4096}} \\&=\frac{48(0.95)}{5} \\&=\frac{48(0.9998)}{5} \\&=\frac{48(0.9998)}{5} \\&=\frac{47.9904}{5} \\&=38.39\end{aligned}$

Thus, the sum of first six terms is 38.39

5 0

3 years ago

isabella has found that she stays the most fit by running variouse dinstances and terrains through out the week. On mondays she

den301095 [7]

Monday . . . . . 2.5 miles
Tuesday . . . . . 4.6
Thursday . . . . 6.75
Saturday . . . . . 4.8

Total = 18.65 miles
Days per week = 4

Average miles per running day = 18.65/4 = 4.6625 miles

Rounded to the nearest 0.01 = 4.66 miles per running day

6 0

3 years ago

In a college of 400 students, 45% are girls. Of the boys, 30% are football players. How many boys are football players?

Archy [21]

Answer:

B. 66

Step-by-step explanation:

45% of 400

.45 x 400 = 180 (number of girls)

400 - 180 = 220 (number of boys)

30% of 220

.30 x 220 = 66

8 0

3 years ago

Read 2 more answers

Solving Expansion Problems using the Distributive Property

svlad2 [7]

1) 2a+18
2) 5-10w
3) -12x+18
4) 2a+1b
5) 16.65+3.7x
6) 2x+12
7) 8x-32
8) 0.9x-0.6+0.36y

7 0

3 years ago