Answer:
And we can find this probability with this difference and using the normal standard table:
Then the answer would be approximately 55.3% of women between the specifications. And that represent more than the half of women
Step-by-step explanation:
Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:
Where and
We are interested on this probability
And the best way to solve this problem is using the normal standard distribution and the z score given by:
If we apply this formula to our probability we got this:
And we can find this probability with this difference and using the normal standard table:
Then the answer would be approximately 55.3% of women between the specifications. And that represent more than the half of women
The equation to solve would be setting
60×- the m plus 75,the b set to 200 the maximum that's wanted to be used. the equation will look like this
200=60x+75
-75. -75
125=60x
125/60 60x/60
2.08=x
and since you cant round the time the answer will be left at 2
17. It would be about 155
20% = 0.20
1254 x 0.20 = 250.80
so he has $250.80 deducted every month