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jeka94
3 years ago
10

Drake received 80 points on a project for school. He can make changes and receive one-tenth of the missing points back. He can d

o this 10 times. Create the formula for the sum of this geometric series, and explain your steps in solving for the maximum grade Drake can receive.
Mathematics
1 answer:
attashe74 [19]3 years ago
4 0
Since Drake is missing points, fixes his project and receives 1/10 of points in total, he can do this 10 times right? Okay, so 80+(# of points he missed)= # of points he can get in total. Since the school curriculum is based on a 100 point grading system, lets assume that 100 will be the max # of points he can get. So the equation will be 80+# of missing points=100. 100 - 80 and we get 20. 20 ÷ 10 = 2. 10 is the amount of times he can fix the project. So since he fixed his project once, he got 2 points more. So the equation is 80 + (2 · 10) = 100
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Question 1 (1 point)
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Answer:

1) 2y^{2}+4y-9

2) 18x^{5}y^{4}z

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Step-by-step explanation:

1) Distribute the negative sign that is outside the parentheses and then you must add like terms, as following:

(y^{2}-3y-5)-(-y^{2}-7y+4)=y^{2}-3y-5+y^{2}+7y-4=2y^{2}+4y-9

2) According to the Product property of exponents, when you multiply powers with the same base, you must add the exponents. Then:

(6xy^{3}z)(3x^{2}yx^{2})=18x^{5}y^{4}z

3) Apply the Distributive property and the Product property of exponents. Then, you obtain:

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4) (4a+5)^{2} is a square of a sum, then, by definition you have:

(a+b)^{2}=a^{2}+2ab+b^{2}

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(4a+5)^{2}=(4a)^{2}+2(4a)(5)+5^{2}=16a^{2}+40a+25

The coefficient of the second term is the number in front of the variable <em>a.</em> Then, the answer is: 40

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(x-4)(x^{2}-3x-9)=x^{3}-3x^{2}-9x-4x^{2}+12x+36=x^{3}-7x^{2}+3x+36

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3 years ago
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Answer:

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Step-by-step explanation:

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4 0
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