Answer:
John is running faster.
Step-by-step explanation:
Given that:
Average Speed of Anne = 6 miles per hour
Speed of John can be represented in the table below:
To find:
Who is running faster of the both i.e. Anne and John?
Solution:
Here, to find the faster runner we can compare the average speed of both the runners.
We are given that, average speed of Anne = 6 miles per hour
We will have to calculate the average speed of John to find the faster runner.
<em>Average speed</em> can be calculated by dividing the total distance traveled with the total time taken.
Total distance traveled by John = 11.5 - 1 = 10.5 miles
Total time taken by John = 1.5 hours
Average speed of John = 
Clearly Average speed of John is greater than that of Anne's.
Therefore, <em>John runs faster</em>.
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Answer: 40.8
Explanation:
I hope this helped!
<!> Brainliest is appreciated! <!>
- Zack Slocum
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<span>Since we need to convert “miles per second” to “miles per hour,” we first need to find out how many seconds there are in a hour.
We know that there are 60 seconds in a minute, and if we wanted to do an hour we would have to do 60 * 60 which is 3600 seconds, therefore,
</span>1 mi/57.1 sec = (1 mi/ 57.1 sec)(3600 sec/1 hour)
= (3600/57.1) mi/hours
<span> = 63.047 mi/hours</span>
Quadratic equations are the equations that can be re arranged in the linear or the standard form.
<u>Explanation:</u>
In algebra, a quadratic equation is any condition that can be adjusted in standard structure as where x speaks to an unknown, and a, b, and c speak to known numbers, where a ≠ 0. On the off chance that a = 0, at that point the condition is straight, not quadratic, as there is no term.
Quadratic equations are really utilized in regular day to day existence, as while ascertaining regions, deciding an item's benefit or figuring the speed of an article. Quadratic conditions allude to conditions with in any event one squared variable, with the most standard structure being ax² + bx + c = 0.
Answer:
12 sec
Step-by-step explanation:
After 1 sec distance between the deer and the bear = (8 + 5) = 13 feet.
After x sec distance is 13x.
13x = 156
x= 156/13=12 sec
