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3 years ago

How to do this problme?

Mathematics

1 answer:

bulgar [2K]3 years ago

8 0

SA=bxh
SA=5x9/2
45/2
22.5 in squared

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yuri has a rope 12 meters long. he cuts it into pieces that are each 2 meters long. what fraction of the rope is one piece

Lelu [443]

So the numerator of your fraction (the top number) is the amount that was cut. The denominator (the bottom number) is the total amount of rope. So, your fraction would be 2/12. You can still simplify that by dividing both the numerator and denominator by 2 and end up with 1/6. Does that make sense? If you need any more help, go ahead and message me :)

6 0

3 years ago

The diagonals of a rhombus measures 6cm and 8cm, what is the perimeter of this rhombus?

Kamila [148]

<h2><u>Diagram</u><u>:</u><u>-</u></h2>

$\setlength{\unitlength}{1 cm}\begin{picture}(20,15)\thicklines\qbezier(1,1)(1,1)(6,1)\qbezier(1,1)(1,1)(1.6,4)\qbezier(1.6,4)(1.6,4)(6.6,4)\qbezier(6,1)(6,1)(6.6,4)\qbezier(6.6,4)(6.6,4)(1,1)\qbezier(1.6,4)(1.6,4)(6,1)\put(0.7,0.5){\sf A}\put(6,0.5){\sf B}\put(1.4,4.3){\sf D}\put(6.6,4.3){\sf C}\end{picture}$

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

The diagonals of the Rhombus= d1 & d2=6cm and 8cm

Let the Side=a

As we know that in a Rhombus

${\boxed{\sf side=\sqrt {\left ({\dfrac{d1}{2}}\right)^2+\left ({\dfrac {d2}{2}}\right)^2}}}$

Substitute the values

${:}\longmapsto$ $\sf a=\sqrt {\left ({\dfrac {6}{2}}\right)^2+\left ({\dfrac {8}{2}}\right)^2 }$

${:}\longmapsto$ $\sf a=\sqrt {(3)^2+(4)^2}$

${:}\longmapsto$ $\sf a=\sqrt {9+16}$

${:}\longmapsto$ $\sf a=\sqrt{25}$

${:}\longmapsto$ $\sf a=5cm$

<h2>_____________</h2><h3>Again </h3>

we know that in a Rhombus

$\boxed{\sf Perimeter=4a}$

Substitute the values

${:}\longmapsto$ $\sf Perimeter=4×5$

${:}\longmapsto$ $\sf Perimeter=20cm$

$\therefore$ Perimeter of the rectangle is 20cm.

5 0

3 years ago

If p = 20 and q = 30, evaluate the following expression:<br> p+q/5

svetlana [45]

Answer:

Step-by-step explanation:

Plug in: $\frac{20+30}{5} = \frac{60}{5} = 12$

7 0

2 years ago

Read 2 more answers

Х- а<br>x-b<br>If f(x) = b.x-a÷b-a + a.x-b÷a - b<br>Prove that: f (a) + f(b) = f (a + b)

GenaCL600 [577]

Given:

Consider the given function:

$f(x)=\dfrac{b\cdot(x-a)}{b-a}+\dfrac{a\cdot(x-b)}{a-b}$

To prove:

$f(a)+f(b)=f(a+b)$

Solution:

We have,

$f(x)=\dfrac{b\cdot(x-a)}{b-a}+\dfrac{a\cdot (x-b)}{a-b}$

Substituting $x=a$ , we get

$f(a)=\dfrac{b\cdot(a-a)}{b-a}+\dfrac{a\cdot (a-b)}{a-b}$

$f(a)=\dfrac{b\cdot 0}{b-a}+\dfrac{a}{1}$

$f(a)=0+a$

$f(a)=a$

Substituting $x=b$ , we get

$f(b)=\dfrac{b\cdot(b-a)}{b-a}+\dfrac{a\cdot (b-b)}{a-b}$

$f(b)=\dfrac{b}{1}+\dfrac{a\cdot 0}{a-b}$

$f(b)=b+0$

$f(b)=b$

Substituting $x=a+b$ , we get

$f(a+b)=\dfrac{b\cdot(a+b-a)}{b-a}+\dfrac{a\cdot (a+b-b)}{a-b}$

$f(a+b)=\dfrac{b\cdot (b)}{b-a}+\dfrac{a\cdot (a)}{-(b-a)}$

$f(a+b)=\dfrac{b^2}{b-a}-\dfrac{a^2}{b-a}$

$f(a+b)=\dfrac{b^2-a^2}{b-a}$

Using the algebraic formula, we get

$f(a+b)=\dfrac{(b-a)(b+a)}{b-a}$ $[\because b^2-a^2=(b-a)(b+a)]$

$f(a+b)=b+a$

$f(a+b)=a+b$ [Commutative property of addition]

Now,

$LHS=f(a)+f(b)$

$LHS=a+b$

$LHS=f(a+b)$

$LHS=RHS$

Hence proved.

5 0

3 years ago

isaac has a piece of rope that is 5 yards long. into how many 1/2 yard pieces of rope can isaac cut the rope

marusya05 [52]

What you have to do is figure out how many half inches you need to have to figure out how many half inches equal 5 yards. Therefore if there are 12 inches in a foot, then that would be 24 half inches. So..... three feet equal 1 yards. So multiply 3 by 24. 3x24=72 so you would need 72 half inches

8 0

4 years ago