Question

Please answer this question for 23 points !! :D

Answer 1

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

$\dfrac{(4^3-2)\times3\div6+4}{2^5-(3^2\times3)}=\dfrac{(64-2)\times3\div6+4}{32-(9\times3)}=\dfrac{62\times3\div6+4}{32-27}\\\\=\dfrac{186\div6+4}{5}=\dfrac{31+4}{5}=\dfrac{35}{5}=7\\\\Answer:\ \boxed{b.\ 7}$