Jack played the first 3/5 of a basketball game. Then he played the final 1/10 of the game
1 answer:
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Answer:
The chance of getting exactly 3 hits is = 0.20
Step-by-step explanation:
P.S - The exact question is -
As given,
F(x) = 0 , x < 1
0.30 , 1 ≤ x < 2
0.56 , 2 ≤ x < 3
0.76 , 3 ≤ x < 4
0.9 , 4 ≤ x < 5
1 , 5 ≤ x
Now,
f(x) = 0.30 , x = 1
0.56 - 0.30 = 0.26 , x = 2
0.76 - 0.56 = 0.20 , x=3
0.9 - 0.76 = 0.14 , x = 4
1 - 0.9 = 0.1 , x = 5
0, otherwise
Now,
The chance of getting exactly 3 hits is = f(x = 3) = 0.20
The correct question in the attached figure
we know that
applying the law of sines
g/sinG=k/sinK
g=3 units
G=30°
k=4 units
K=?
so
g/sinG=k/sinK------> g*sinK=k*sinG-----> sinK=k*sinG/g
sinK=4*sin 30°/3-----> 2/3
K=arc sin(2/3)-------> K=41.81°
case 1)
for angle K=41.81°
the sum of the angles (H +G+K)=180°
H=180-(G+K)------> 180-(30+41.81)--------> H=108.19°
h/sinH=g/sinG-------> h=g*sinH/sinG------> h=3*sin 108.19°/sin 30°
h=5.70 units
case 2)
for angle K=180°-41.81°---------> K=138.19°
the sum of the angles (H +G+K)=180°
H=180-(G+K)------> 180-(30+138.19)--------> H=11.81°
h/sinH=g/sinG-------> h=g*sinH/sinG------> h=3*sin 11.81°/sin 30°
h=1.2 units
therefore
the answer is the option
<span>A. 1.2 or 5.7</span>
we know that
applying the law of sines
g/sinG=k/sinK
g=3 units
G=30°
k=4 units
K=?
so
g/sinG=k/sinK------> g*sinK=k*sinG-----> sinK=k*sinG/g
sinK=4*sin 30°/3-----> 2/3
K=arc sin(2/3)-------> K=41.81°
case 1)
for angle K=41.81°
the sum of the angles (H +G+K)=180°
H=180-(G+K)------> 180-(30+41.81)--------> H=108.19°
h/sinH=g/sinG-------> h=g*sinH/sinG------> h=3*sin 108.19°/sin 30°
h=5.70 units
case 2)
for angle K=180°-41.81°---------> K=138.19°
the sum of the angles (H +G+K)=180°
H=180-(G+K)------> 180-(30+138.19)--------> H=11.81°
h/sinH=g/sinG-------> h=g*sinH/sinG------> h=3*sin 11.81°/sin 30°
h=1.2 units
therefore
the answer is the option
<span>A. 1.2 or 5.7</span>