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3 years ago

Help Me quick please!!!

Mathematics

2 answers:

Musya8 [376]3 years ago

7 0

Let the width of room be =x mtrs

Then the length is x+2 mtrs

As Perimeter = 2(l+b) = 2(x+x+2)

16 = 2 ( 2x+2)

16/2 = 2x +2

8=2x+2

2x= 8-2 = 6

x = 6/2 =3 mtrs

Therefore width of the room is 3 mtrs

Arte-miy333 [17]3 years ago

6 0

2(w)+ 2(w+2)=16

2w + 2w +4 =16

4w + 4 =16

4w = 12

w =3

width = 3 meters

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sergij07 [2.7K]

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3 years ago

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Anna, Beth and Colleen are softball players. This season, Anne had 65 base hits in 160 at-bats. Beth batting average was 0.399,

zheka24 [161]

Answer:

Anne is the best hitter as she has the best hitting average of 0.406

Step-by-step explanation:

Anne hits 65 bases out of 160 at - bats.

Beth's betting average = 0.399

Collin's hit = 40%

Now, we need to convert all the three hitting rates into same parameters to compare them with each other.

Average hit rate of Anne = $\frac{\textrm{Total numberof base}}{\textrm{Total number of at - bats}}$

$= \frac{65}{160} = 0.406$

⇒The betting average of Anne = 0.406

Now, The hit - rate of Collin = 40%

Converting the percentage rate into decimal, we get the hit rate of Collin

= $\frac{40}{100} = 0.40$

Hence, we get that Hitting Average of :

<u>Anne = 0.406</u>, Beth = 0.3999 and Collin = 0.400

Hence, from the above data Anne is the best hitter as she has the best hitting average of 0.406.

6 0

3 years ago

Read 2 more answers

You roll 4 fair, distinguishable, six-sided dice. What is the probability of rolling :______

Vikentia [17]

Answer:

a)0.25

b)0.375

Step-by-step explanation:

Possible outcomes when dice are rolled : 1 ,2 ,3,4,5 ,6

Even= 2,4,6

Odd = 1 ,3 , 5

Probability of getting even = $\frac{3}{6}=\frac{1}{2}$

Probability of getting odd = $\frac{3}{6}=\frac{1}{2}$

4 dices are rolled together

a)P(3 even and 1 odd numbers)

P(3 even and 1 odd numbers)= $^4C_3 (\frac{1}{2})^3 (\frac{1}{2})^1$

P(3 even and 1 odd numbers)= $\frac{4!}{3!1!} (\frac{1}{2})^3 (\frac{1}{2})^1 =0.25$

b)P(2 even and 2 odd numbers)

P(2 even and 2 odd numbers)= $^4C_2 (\frac{1}{2})^2 (\frac{1}{2})^2$

P(3 even and 1 odd numbers)= $\frac{4!}{2!2!} (\frac{1}{2})^2 (\frac{1}{2})^2$ =0.375

6 0

2 years ago

Which of the following expressions can be factored by grouping? (Select all that apply.)

Greeley [361]

Answer:

Options (3), (4) and (5)

Step-by-step explanation:

1). a² - 9a + 7ab + 63b

= a(a - 9) + 7b(a + 9)

Now we can not solve this problem further.

Therefore, can't be factored by grouping.

2). 3a + 4ab - b - 12

= a(3 + 4b) - 1(b - 12)

We can't solve it further.

Therefore, can't be factored by grouping.

3). ab + 6b - 2a - 12

= b(a + 6) - 2(a + 6)

= (b - 2)(a + 6)

We can be factored this expression by grouping.

4). x³ + 9x²+ 7x + 63

= x²(x + 9) + 7(x + 9)

= (x² + 7)(x + 9)

Therefore, the given expression can be factored by grouping.

5). ay² + a - y² - 1

= a(y² + 1) - 1(y² + 1)

= (a - 1)(y² + 1)

This expression can be factored by the grouping method.

Options (3), (4) and (5) are the correct answers.

3 0

3 years ago

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Bad White [126]

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I'm not sure for the second one but I think 1 ft

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3 years ago