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dlinn [17]
3 years ago
8

Subtract. Write the difference in simplest form. (6p + 3) - (2p + 1)

Mathematics
1 answer:
Sonja [21]3 years ago
3 0

Answer:

4p + 2

Step-by-step explanation:

(6p + 3) - (2p + 1)

Distribute the minus sign

6p +3 -2p -1

4p +2

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What are the zeros of the function f(x)=x^2-2x-15?
valkas [14]
To find the zeros of this function, we must first set the entire function equal to 0

f(x) = x² - 2x - 15 = 0

Since this is a quadratic function, we must use the quadratic formula, which is:

\frac{-b +/-  \sqrt{b^{2} - 4(a)(c) } }{2a}

Let's assign a, b, and c using our first function
x² means a = 1 (because it could be written as 1x²)
-2x means b = -2
-15 means c = -15

Now let's plug those in:

\frac{-(-2) +/- \sqrt{(-2)^{2} - 4(1)(-15) } }{2(1)}

which simplifies to:

\frac{2 +/- \sqrt{(4 + 60} }{2}

Simplified further:

\frac{2 +/- \sqrt{(64} }{2}
\frac{2 +/- 8 }{2}
And divide it by the 2 on the bottom gives us:

2 +/- 4

2+4 = 6
2-4 = -2

So the zeros of this function are -2 and 6
6 0
3 years ago
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595 is the number of at bats he would have in the season.
8 0
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If x° and 60° are vertically opposite angles , then x° = ?​
Lynna [10]

Answer:

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Step-by-step explanation:

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If the equation is solved, which is true? (Round to the nearest tenth as needed)
Tanya [424]

Answer:

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5 0
3 years ago
Factorize :3y²-54y+343​
arlik [135]

1 In general, given

a

x

2

+

b

x

+

c

ax

2

+bx+c, the factored form is:

a

(

x

−

−

b

+

b

2

−

4

a

c

2

a

)

(

x

−

−

b

−

b

2

−

4

a

c

2

a

)

a(x−

2a

−b+

b

2

−4ac

​

​

)(x−

2a

−b−

b

2

−4ac

​

​

)

2 In this case,

a

=

3

a=3,

b

=

−

54

b=−54 and

c

=

343

c=343.

3

(

y

−

54

+

(

−

54

)

2

−

4

×

3

×

343

2

×

3

)

(

y

−

54

−

(

−

54

)

2

−

4

×

3

×

343

2

×

3

)

3(y−

2×3

54+

(−54)

2

−4×3×343

​

​

)(y−

2×3

54−

(−54)

2

−4×3×343

​

​

)

3 Simplify.

3

(

y

−

54

+

20

3

ı

6

)

(

y

−

54

−

20

3

ı

6

)

3(y−

6

54+20

3

​



​

)(y−

6

54−20

3

​



​

)

4 Factor out the common term

2

2.

3

(

y

−

2

(

27

+

10

3

ı

)

6

)

(

y

−

54

−

20

3

ı

6

)

3(y−

6

2(27+10

3

​

)

​

)(y−

6

54−20

3

​



​

)

5 Simplify

2

(

27

+

10

3

ı

)

6

6

2(27+10

3

​

)

​

to

27

+

10

3

ı

3

3

27+10

3

​



​

.

3

(

y

−

27

+

10

3

ı

3

)

(

y

−

54

−

20

3

ı

6

)

3(y−

3

27+10

3

​



​

)(y−

6

54−20

3

​



​

)

6 Factor out the common term

2

2.

3

(

y

−

27

+

10

3

ı

3

)

(

y

−

2

(

27

−

10

3

ı

)

6

)

3(y−

3

27+10

3

​



​

)(y−

6

2(27−10

3

​

)

​

)

7 Simplify

2

(

27

−

10

3

ı

)

6

6

2(27−10

3

​

)

​

to

27

−

10

3

ı

3

3

27−10

3

​



​

.

3

(

y

−

27

+

10

3

ı

3

)

(

y

−

27

−

10

3

ı

3

)

3(y−

3

27+10

3

​



​

)(y−

3

27−10

3

​

I hope this help you

​

6 0
2 years ago
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