Answer:
[C] 
Step-by-step explanation:
The ray in the terminal position, after the rotation is call the "terminal side of the angle."
Note that quadrant of the unit circle of any given angle the radians would be in:
Quad I → 0 < θ < pi/2
Quad II → pi/2 < θ < pi
Quad III → pi < θ < 3pi/2
Quad IV → 3pi/2 < θ < 2pi
Hence, Answer is [C] pi/2 radians
<u><em>~lenvy~</em></u>
Answer:
x = 8 units.
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one.
<em>The areas of the squares adjacent to two sides of a right triangle are 32 unit square and 32 units square. Find the length,x, of the third side of the triangle</em>
My answer:
- Let a is the side length of the 1st square
The area of the 1st square is equal to 32 units square
<=>
<=> a =
units
- Let b is the length of the 2nd square
The area of the 2nd square is equal to 32 units square
<=>
= 32
<=> b =
units
Applying the Pythagoras Theorem, we have:
<=>
<=> 
<=> x = 8 units
Hope it will find you well.
Answer:
x = 6 and x = 11.
Step-by-step explanation:
sqrt(x - 2) + 8 = x
sqrt(x - 2) = x - 8
(sqrt(x - 2))^2 = (x - 8)^2
x - 2 = x^2 - 16x + 64
x^2 - 16x + 64 = x - 2
x^2 - 17x + 66 = 0
We can use the discriminant to find whether there are solutions to the equation.
b^2 - 4ac; where a = 1, b = -17, and c = 66.
(-17)^2 - 4 * 1 * 66
= 289 - 264
= 25
Since the discriminant is positive, we know there are two valid solutions to the equation.
x^2 - 17x + 66 = 0
(x - 6)(x - 11) = 0
The solutions are when x - 6 = 0 and x - 11 = 0.
x - 6 = 0
x = 6
x - 11 = 0
x = 11
Hope this helps!
Answer: yes it is
Step-by-step explanation:
Answer:
m= -3
Step-by-step explanation:
using slope formula (Y2-Y1)/(X2-X1)
(9-3)/(8-10)
6/-2
m= -3