Question

How to solve 7(4×1/2)+3(5×1/3)+2(-3×1/2

Answer 1

Multiple: 4 * 1 /2  = 4 · 1  = 4 /2  = 2 · 2

                             1 · 2              1 · 2  = 2

Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD(4, 2) = 2

Multiple: 7 * 2 = 14

Multiple: 5 * 1 /3  = 5 · 1

                             1 · 3  = 5 /3

Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD(5, 3) = 1

Multiple: 3 * 5 /3  = 3 · 5

                              1 · 3  = 15 /3  = 5 · 3

                                                    1 · 3  = 5

Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD(15, 3) = 3

Add: 14 + 5 = 19

Multiple: -3 * 1 /2  = -3 · 1

                               1 · 2  = -3 /2 = -1.5 · 2

                                                       1 · 2

Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD(-3, 2) = 2

Multiple: 1/2 * (-3 /2 ) = 2 · (-3)

                                    1 · 2  = -6 /2  = -3 · 2

                                                           1 · 2  = -3

Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD(-6, 2) = 2

Add: 19 + (-3) = 16

7(4×1/2) + 3(5×1/3) + 2(-3×1/2) = 16 /1  = 16