You have the ratio set up correctly:
2x+2/12 = x+3/21
Now cross multiply:
2x+2 * 12 = x+3 * 21
Simplify:
24x + 24 = 21x + 63
Subtract 24 from each side:
24x = 21x + 39
Subtract 21x from each side:
3x = 39
Divide both sides by 3:
x = 39/3
x = 13
Answer:
![\frac{1}{6\\}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B6%5C%5C%7D)
Explanation:
Probability = ![\frac{Number of outcomes}{Total possible outcomes}](https://tex.z-dn.net/?f=%5Cfrac%7BNumber%20of%20outcomes%7D%7BTotal%20%20%20%20%20%20possible%20%20%20%20%20%20%20%20outcomes%7D)
In this case Number of outcomes is 1, that is 6
And total number of outcomes = 6 (Because there are six sides of a dice)
So the probability = ![\frac{1}{6\\}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B6%5C%5C%7D)
Hope it helps :)
Answer:
![Volume = 48in^3](https://tex.z-dn.net/?f=Volume%20%3D%2048in%5E3)
Step-by-step explanation:
Given
See attachment for box
Required
The volume of the box
The number of boxes in each direction represents the length of that dimension.
So, from the attachment
![Width = 4in](https://tex.z-dn.net/?f=Width%20%3D%204in)
![Length = 3in](https://tex.z-dn.net/?f=Length%20%3D%203in)
![Height = 4in](https://tex.z-dn.net/?f=Height%20%3D%204in)
The volume is:
![Volume = Length * Width * Height](https://tex.z-dn.net/?f=Volume%20%3D%20Length%20%2A%20Width%20%2A%20Height)
![Volume = 4in * 3in * 4in](https://tex.z-dn.net/?f=Volume%20%3D%204in%20%2A%203in%20%2A%204in)
![Volume = 48in^3](https://tex.z-dn.net/?f=Volume%20%3D%2048in%5E3)