What is the result of isolating y^2 in the equation below (x+6)^2+y^2=1
1 answer:
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Answer:
The speed of the tyre of the car is 1002.24 feet per minute .
Step-by-step explanation:
Given as :
The radius of the car wheel = r = 16 inches
Since 12 inches = 1 feet
So, 16 inches = ×16 = 1.33 feet
The number of revolution of the wheel = 120 revolution per minute
Let The speed of the wheel = s feet per minute
The circumference of wheel = 2 × × radius
where = 3.14
or, circumference = 2 × 3.14 × 1.33
Or, Circumference = 8.352 feet
Now , Speed = circumference of wheel × number of revolution
or, Speed = 8.352 feet × 120 revolution per minute
∴ Speed = 1002.24 feet per minute
Hence The speed of the tyre of the car is 1002.24 feet per minute . Answer
Whatever% of anything is just (whatever/100) * anything.
x = ounces of 14% iodine.
y = ounces of 29% iodine.
we know that in a 14% iodine solution, 14% is iodine and the rest is something else, we also know that "x" ounces of the solution have 14% of iodine, how much is that? (14/100) * x, or 0.14x.
likewise, in the 89 ounces of 47% solution there is (47/100) * 89 of iodine.
and likewise as well, in "y" ounces of 29% iodine there is (29/100) * y, or 0.29y of iodine.
bearing in mind that, whatever "x" and "y" may be, x + 89 = y, and that the sum of the iodine amounts also will equate 0.29y.
x = ounces of 14% iodine.
y = ounces of 29% iodine.
we know that in a 14% iodine solution, 14% is iodine and the rest is something else, we also know that "x" ounces of the solution have 14% of iodine, how much is that? (14/100) * x, or 0.14x.
likewise, in the 89 ounces of 47% solution there is (47/100) * 89 of iodine.
and likewise as well, in "y" ounces of 29% iodine there is (29/100) * y, or 0.29y of iodine.
bearing in mind that, whatever "x" and "y" may be, x + 89 = y, and that the sum of the iodine amounts also will equate 0.29y.