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3 years ago

What is 1/10 of 0.09

Mathematics

2 answers:

Rus_ich [418]3 years ago

8 0

Of means to Multiply so
1/10 x 0.09 = 9/1000 as a fraction and 0.009 as a decimal

densk [106]3 years ago

6 0

Convert 0.09 to a fraction first:

.09=9/100

Then multiply the two together:

1/10 x 9/100 = 9/1000, or 0.009

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Please help find and plot the reflection of this. I will mark brainliest

lubasha [3.4K]

Answer:

Look below for coordinates

Step-by-step explanation:

A: -2, 3 to A': -2, -3

B: 5, -2 to B': 5, 2

C: -5, 1 to C': -5, -1

Reflect over x-axis: (x, -y) and Reflect over y-axis: (-x, y)

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3 years ago

What is the equation of the line that passes through the point (8,4) and has a slope of 3/2

iren [92.7K]

Answer: Y= 3/2x-8=

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3 years ago

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Firlakuza [10]

Answer:

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Step-by-step explanation:

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3 years ago

EXPLAIN why we placed the value of x= 4/3( the minimum value) into the equ of gradient(dy/dx) [in the answer, marking scheme att

aliina [53]

$y=x(x-2)^2$
$\implies y'=(x-2)^2+2x(x-2)=3x^2-8x+4=(3x-2)(x-2)=0$
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are the critical points, and judging by the picture alone, you must have $b=\dfrac23$ and $a=2$ . (You might want to verify with the derivative test in case that's expected.)

Then the shaded region has area

$\displaystyle\int_0^2x(x-2)^2\,\mathrm dx=\dfrac43$

I'll leave the details to you.

Now, for part (iv), you're asked to find the minimum of $\dfrac{\mathrm dy}{\mathrm dx}=y'$ , which entails first finding the second derivative:

$y'=3x^2-8x+4$
$\implies y''=6x-8$

setting equal to 0 and finding the critical point:

$6x-8=0\implies x=\dfrac86=\dfrac43$

This is to say the minimum value of $\dfrac{\mathrm dy}{\mathrm dx}$ *occurs when $x=\dfrac43$ *, but this is not necessarily the same as saying that $\dfrac43$ is the actual minimum value.

The minimum value of $\dfrac{\mathrm dy}{\mathrm dx}$ is obtained by evaluating the derivative at this critical point:

$m=\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=4/3}=3\left(\dfrac43\right)^2-8\left(\dfrac43\right)+4=-\dfrac43$

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4 years ago

How do I do this? I don't understand how to do this?

Scorpion4ik [409]

These are the angle measurements, hope this helps you and let me know if im wrong

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3 years ago