This is a standard deviation contest. Which of the following sets of four numbers has the smallest possible standard deviation?

Mathematics

1 answer:

Maksim231197 [3]2 years ago

6 0

B option is right I think.

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Please help solve for PQ.

DerKrebs [107]

This problem cannot be solved unless we are given figure NPQR is a rhombus.
In that case, then all sides are equal, meaning
5x+16=9x-32
Solve for x
9x-5x=16+32
4x=48
x=12

Each side (including PQ) then equals 5x+16=5*12+16=76

8 0

2 years ago

Find the solution set of the following quadratic equations using the quadratic formula.

oksian1 [2.3K]

Answer:

<h3> 1) $x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2$ </h3><h3> 2) $x_1=-\dfrac13\,,\quad x_2=-3$ </h3>

Step-by-step explanation:

$x^2 - 7x + 9 = 0\quad\implies\quad a=1\,,\ b = -7\,,\ c=9\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-(-7)\pm\sqrt{(-7)^2-4\cdot1\cdot9}}{2\cdot1}=\dfrac{7\pm\sqrt{49-36}}2\\\\x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2$

<h3>2)</h3><h3> $3x^2 + 10x=-3\\\\3x^2+10x+3=0\quad\implies\quad a=3\,,\ b =10\,,\ c=3\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-10\pm\sqrt{10^2-4\cdot3\cdot3}}{2\cdot3}= \dfrac{-10\pm\sqrt{100-36}}6\\\\x_1=\dfrac{-10+\sqrt{64}}6=\dfrac{-10+8}6=-\dfrac13\,,\qquad x_2=\dfrac{-10-8}6=-3$ </h3>

7 0

3 years ago

What's 5.78,-5 7/8,-5.9 from least to greatest?

blagie [28]

-5.9, -5 7/8, 5.78 because negative is less than zero and 7/8= .850 :)

3 0

2 years ago

Please help thank you

zlopas [31]

Answer:

A is the real part and B is the imaginary part. i is an imaginary figure. b is how many imaginary figures there are, making it represent an imaginary part

3 0

2 years ago

How are 1/4 of 12 and 12 divided by 4 related????

Jobisdone [24]

Both expressions are related because 12 divided by 4 equals to 3, and 1/4 of 12 equals to 3 too.

3 0

2 years ago