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hichkok12 [17]
3 years ago
10

Can someone please check my answer thank you

Mathematics
1 answer:
Dima020 [189]3 years ago
4 0

Answer:

(0, 2) and (- 1, 4)

Step-by-step explanation:

The solutions to the system of equations are at the points of intersection of f(x) and g(x)

These are at (0, 2) and (- 1, 4)



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The area of a rectangle is represented by the polynomial x^2+3x-6x-18. What are the length, width, and area of the rectangle if
Nitella [24]

Answer:

Length = 15

Width = 6

Area = 90

Step-by-step explanation:

Area of the rectangle = {x}^{2}  + 3x - 6x - 18

Lets factorise the polynomial

=  >  x(x + 3) - 6(x + 3)

=  > (x  + 3)(x - 6)

We know that Area = Length × Width

Let the length be (x + 3) & width be (x - 6)

Its given in the question that x = 12. So putting the value of x gives ,

Length = x + 3 = 12 + 3 = 15

Width = x - 6 = 12 - 6 = 6

Area = Length × Width = 15 × 6 = 90

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Question 13 y-5x= -4
Julli [10]

Which variable are we solving for?

For y:

y= 5x-4/ 13


For x:

x= 13y+4/ 5



5 0
3 years ago
There were 350 members in the high
anastassius [24]

Answer:

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In circle A shown, BC || DE , mBC=58° and mDE=142°. Determine the measure of ZCFE . Show how you arrived at your answer.
AysviL [449]

Answer:

< CFE = 40°

Step-by-step explanation:

To better understand the solution, see attachment for the diagram.

Given:

BC parallel to DE

Measure of Arc BD = 58°

Measure of Arc DE = 142°

First step: Draw a diameter that passes through the centre of the circle and name it. In this case, the diameter is line ST.

The line ST divides the arc BD and arc DE into half.

That is:

Arc SC = 1/2(arc BC) =1/2(58)

Arc SC = 29°

Arc TE = 1/2(arc DE) =1/2(142)

Arc TE = 71°

Arc SC + Arc CE + Arc TE = 180° (Sum of angles in a semicircle

29° + Arc CE  + 71° = 180°

Arc CE + 100° = 180°

Arc CE = 180-100

Arc CE = 80°

Inscribed angle = 1/2(intercepted angle)

<CFE = 1/2(Arc CE )

<CFE = 1/2(80)

< CFE = 40°

5 0
3 years ago
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