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3 years ago

5 2/3 divided by -1 2/15

Mathematics

1 answer:

Katyanochek1 [597]3 years ago

7 0

$5\frac{2}{3}:(-1\frac{2}{15})=\frac{5\times3+2}{3}:(-\frac{1\times15+2}{15})=\frac{15+2}{3}:(-\frac{15+2}{15})\\\\=\frac{17}{3}:(-\frac{17}{15})=\frac{17}{3}\times(-\frac{15}{17})=\frac{1}{3}\times(-\frac{15}{1})=-\frac{15}{3}=-5$

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Find the zeroes of the polynomial using the quadratic formula.

babymother [125]

Answer:

Step-by-step explanation:

2x² - 3x - 15 = 5

2x² - 3x - 20 = 0

Quadratic formula

x = [3 ± √(3² – 4·2(-20))] / [2·2]

= [3 ± √169] / 4

= [3 ± 13] /4

= -2.5, 4

6 0

3 years ago

PLS HELP ME WITH MATH

arsen [322]

Answer:

slope is 3

Step-by-step explanation:

Slope = $\frac{change in y }{change in x }$

change in y = (13-7), (19-13), (25-19), (31-25)

change in y = 6

Change in x = (4-2), (6-4), (8-6), (10-8)

Change in x = 2

Therefore slope = $\frac{6}{2}$

Slope = 3

5 0

2 years ago

The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

$T_6$

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

$\frac{T_7}{T_5} = \frac{40}{160}$

Divide the numerator and the denominator of the fraction by 40

$\frac{T_7}{T_5} = \frac{1}{4}$ ----- equation 1

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Where n is the nth term

So,

$T_7 = a r^{6}$

$T_5 = a r^{4}$

Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

Next, is to solve for the first term;

Using $T_5 = a r^{4}$

By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

We get

$160 = a \frac{1}{2}^{4}$

$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

$2560 = a$

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

$T_6 = 2560( \frac{1}{32})$ or $T_6 = 2560( \frac{-1}{32})$

$T_6 = 80$ or $T_6 = -80$

$T_6 =$ ±80

Hence, the 6th term is positive/negative 80

8 0

3 years ago

Examine the system of equations. y = 4x + 8, y = 4x – 1 Which statements best describe the two expressions? Check all that apply

Lerok [7]

Answer:

The correct statements are as follows;

1. They have different y-intercepts

2. The substitution method results in false statement 8 = -1

3. There is no solution

Step-by-step explanation:

Here, we want to select the statement that best describes the equations

The equation for a straight line is generally;

y = mx + b

m is slope and b is the y-intercept

slope of both is same ; 4

So first assertion is wrong

they have different y-intercepts

First y-intercept is 8, second is -1

This is correct

The third statement is correct too

if we equated both y;

4x + 8 = 4x -1

We shall have 4x canceled out and left with 8 = -1

(8,-1) is not a solution

There is no solution is correct because after substituting, we have 8 = -1 which is not correct and also impossible

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3 years ago

HELP!<br> -1/4 × (-7/9)

boyakko [2]

Answer:

I hope this is helps.

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3 years ago