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mr Goodwill [35]
3 years ago
5

If the great circle circumference of a sphere is 16pie yards, find its surface area

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
5 0

Answer:

Step-by-step explanation:

The circumference of a circle = 2*pi * r

so 16 pi yards = 2 * pi * r

Divide both sides by 2

16 pi/2 = 2*pi * r /2

8*pi =  pi * r    

Divide both sides by pi

8 * pi / pi = pi * r / pi

r = 8

====================

Surface Area = 4 pi * r^2

r = 8

Surface Area = 4 * pi * 64

Surface Area = 256 * pi

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The maximum wingspan in millimeters would be 160.

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King  Kilo
Henry  Hecto 
Died  Deca
Drinking  Deci
Chocolate Centi
Milk   Milli 

Since Centi is greater than Milli by one space, you increase by ten, which means you move the decimal once to the right. 

Hope this helps! :)
4 0
3 years ago
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Simplify 12^3/12^7<br> A. 12^4<br> B 1/12^4<br> C 1/12^-4<br> D 12^10
mrs_skeptik [129]
The answer is B.

Explanation:

If you divide exponents, you subtract the exponents.
8 0
3 years ago
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What is 1.04 as a percent
zavuch27 [327]
If you convert the number on a percent,
then multiply the number by 100 with sign %

1.04 = 1.04 × 100% = <u>104%</u>

4 0
2 years ago
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The grasshopper jumps either one block to the north, or one block to the west. He needs to reach the point that is located four
Pavel [41]

Answer:

The number of ways the grasshopper can reach the desired destination are 9 ways

Step-by-step explanation:

The directions in which the grasshopper can jump are;

One block north  and one block west

By counting, we have;

The number of possible ways are through blocks

1) 1, 2, 5, 6, 8, 10

2) 1, 2, 5, 6, 8, 9

3) 1, 2, 5, 6, 7, 9

4) 1, 2, 3, 6, 8, 10

5) 1, 2, 3, 6, 8, 9

6) 1, 2, 3, 6, 7, 9

7) 1, 2, 3, 4, 7, 9

8) 15, 14, 16, 12, 11, 10

9) 12, 13, 16, 12, 11, 10

Therefore, there 9 ways the grasshopper can reach the desired destination.

3 0
2 years ago
Find the x-intercepts of the parabola with vertex (1,-108) and y-intercept (0,-105). Write your answer in this form: (X1,y1), (x
Stolb23 [73]

Answer:

(7, 0) and (-5, 0)

Step-by-step explanation:

<u>Vertex form</u>

y=a(x-h)^2+k  

(where (h, k) is the vertex)

Given:

  • vertex = (1, -108)

\implies y=a(x-1)^2-108

Given:

  • y-intercept = (0, -105)

\implies a(0-1)^2-108=-105

\implies a(-1)^2=-105+108

\implies a=3

Therefore:

\implies y=3(x-1)^2-108

The x-intercepts are when y = 0

\implies 3(x-1)^2-108=0

\implies 3(x-1)^2=108

\implies (x-1)^2=36

\implies x-1=\pm \sqrt{36}

\implies x=1\pm 6

\implies x=7, x=-5

Therefore, the x-intercepts are (7, 0) and (-5, 0)

7 0
2 years ago
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