Answer:
C. x + 1 < 5; x < 4
Step-by-step explanation:
Since he already got 1 C, he can only have 3 more. Since x has to be <em>less than 4</em>, that rules out B and D instantly. A is ruled out because x can't be equal to 4 since you need less than 5 C's to get into UGA.
Hope this helps. :)
Answer:
true for all x
Step-by-step explanation:
3x - 4 ≤ 2
Add 4 to each side
3x - 4+4 ≤ 2+4
3x<6
Divide by 3
3x/3 <6/3
x<2
or
2x + 11 ≥ -1
Subtract 11 from each side
2x + 11-11 ≥ -1-11
2x≥ -12
Divide by 2
2x/2 ≥ -12/2
x ≥ -6
x<2 or x ≥ -6
true for all x
Answer:
X>-14
Step-by-step explanation:
Just had to solve it