Answer:
We need a sample size of 564.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

The margin of error is:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
Based upon a 95% confidence interval with a desired margin of error of .04, determine a sample size for restaurants that earn less than $50,000 last year.
We need a sample size of n
n is found when 
So






Rounding up
We need a sample size of 564.
triangles ABC AND MAc the right angle and angle b
Missing informations but this can be turned into y=4x-12
Answer:
6n +7
Step-by-step explanation:
You cannot solve since this is an expression, you can only simplify
-2(-3-3n)+1
Distribute the -2
-2*-3 -2*-3n +1
6 +6n +1
Combine like terms
6n +7
If sine (theta) = 4/7 then theta is found by:
arc sine (4/7) = theta
theta = 34.85 Degrees
cosine (34.85) = 0.82065