I do not know bro. Have you tried
Step-by-step explanation:
Total Surface area of a pyramid is given as
= Lateral surface area + area of base.
Lateral surface area = 1/2×perimeter of base×slant height
given the base is square with side 9 in , and slant height of 12 inches.
therefore, LSA = 1/2(9*4)×12 = 216 in^2
Now, TSA = LSA + Base area = 216+9^2 = 297 in^2
a) It is given that the pyramid is smaller therefore, it will require lesser paint than the original pyramid ( The TSA of the smaller pyramid cannot be calculated as its dimentions are not given).
b) It can not be solved as dimensions are missing in the question.
However, the logic has been explained in the soluion one easily put values to find the solution.
A)
Let x represent the cost of 1 student, and y the cost of 1 teacher.
B)
In the first group, there's 25 students and 2 teachers. Their total cost is $97.50
So 25x + 2y = 97.50
In the second group, there's 32 students and 3 teachers. Their total cost is $127
So 32x + 3y = 127
We get the following system of equations:
25x + 2y = 97.50 (1)
32x + 3y = 127 (2)
C)
25x + 2y = 97.50 (1)
32x + 3y = 127 (2)
In equation (1)
25x + 2y = 97.50
25x + 2y - 2y = 97.50 - 2y
25x = 97.50 - 2y
25x / 25 = 97.50/25 - 2y/25
x = 3.9 - (2/25)y
In equation (2), let's replace x by its algebraic value
32x + 3y = 127
32(-2/25y + 3.9) + 3y = 127
11/25y + 124.8 = 127
11/25y + 124.8 - 124.8 = 127 - 124.8
11/25y = 2.2
(11/25y) / (11/25) = 2.2 / (11/25)
y = 5
x = -2/25y + 3.9
x = -2/25 * 5 + 3.9
x = 3.5
So the cost of each student is $3.5, and the cost of each teacher is $5.
Hope this helps! :)
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Answer:
y > -x + 3
Step-by-step explanation:
find the slope and y-intercept so you can create a linear equation:
y = mx + b ; m = slope and b = y-intercept
slope (m) = (3-0) / (0-3)
m = 3/-3 or -1
we can see the y-intercept by looking at the graph, it is 3
y > -x + 3