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SpyIntel [72]
3 years ago
12

Which choice is equivalent to the product below?

Mathematics
1 answer:
posledela3 years ago
7 0
\bf \sqrt{\cfrac{3}{16}}\cdot \sqrt{\cfrac{3}{9}}\implies \cfrac{\sqrt{3}}{\sqrt{16}}\cdot \cfrac{\sqrt{3}}{\sqrt{9}}\implies \cfrac{\sqrt{3}}{4}\cdot \cfrac{\sqrt{3}}{3}\implies \cfrac{\sqrt{3}\cdot \sqrt{3}}{4\cdot 3}
\\\\\\
\cfrac{(\sqrt{3})^2}{12}\implies \boxed{\cfrac{3}{12}}\implies \stackrel{simplified}{\cfrac{1}{4}}
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Luden [163]
Its b because yeah im just kidding idk im really stupid jk its b hahaha 

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3 years ago
Wouldnt the answer be A or B? Right?​
VMariaS [17]

Answer:

its b

Step-by-step explanation:

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Suppose that an airline uses a seat width of 16.5 in. Assume men have hip breadths that are normally distributed with a mean of
Alexxx [7]

Answer:

a) 0.018

b) 0            

Step-by-step explanation:

We are given the following information in the question:

Mean, μ =  14.4 in

Standard Deviation, σ = 1 in

We are given that the distribution of breadths is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(breadth will be greater than 16.5 in)

P(x > 16.5)

P( x > 16.5) = P( z > \displaystyle\frac{16.5 - 14.4}{1}) = P(z > 2.1)

= 1 - P(z \leq 2.1)

Calculation the value from standard normal z table, we have,  

P(x > 16.5) = 1 - 0.982 = 0.018 = 1.8\%

0.018 is the probability that if an individual man is randomly​ selected, his hip breadth will be greater than 16.5 in.

b) P( with 123 randomly selected​ men, these men have a mean hip breadth greater than 16.5 in)

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}  

P(x > 16.5)  

P( x > 16.5) = P( z > \displaystyle\frac{16.5-14.4}{\frac{1}{\sqrt{123}}}) = P(z > 23.29)  

= 1 - P(z \leq 23.29)

Calculation the value from standard normal z table, we have,  

P(x > 16.5) = 1 - 1 = 0

There is 0 probability that 123 randomly selected men have a mean hip breadth greater than 16.5 in

4 0
3 years ago
Please help i put a picture below
PSYCHO15rus [73]

Answer:

Step-by-step explanation:

This is not nearly as threatening and scary as I first thought it was.  You must be in the section in Geometry where you are taught that perimeter of similar figures exist in a one-to-one relationship while areas of similar figures exist in a squared-to-squared relationship.  We will use that here.  

The area formula for a regular polygon is

A=\frac{1}{2}ap where a is the apothem and p is the perimeter.  We are first asked for the area of the polygon, but it would make more sense to find the perimeter first, since we need it to find the area.

P = 5(8) so

P = 40

We are given that the area of the triangle inside that polygon is 22.022 units squared.  Knowing that the area formula for a triangle is

A=\frac{1}{2}bh we can sub in what we know and solve to find the height:

22.022=\frac{1}{2}(8)h and

22.022 = 4h so

h = 5.5055 units

It just so happens that the height of that triangle is also the apothem of the polygon, so now we have what we need to find the area of the polygon:

A=\frac{1}{2}(5.5055)(40)

which gives us an area of

A = 110.11 units squared.

Here is where we can use what we know about similar figures and the relationships between perimeters and areas.  We will set up a proportion with the smaller polygon info on top and the larger info on bottom.  We know that the larger is 3 times the smaller, so the ratio of smaller to larger is

\frac{s}{l}:\frac{1}{3}

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\frac{s}{l}:\frac{1}{3}=\frac{40}{x}

Cross multiply to get that the perimeter is 120 units.  You could also have done this by knowing that if the larger is 3 times the size of the smaller, then the side measure of the larger is 24, and 24 * 5 = 120.  But we used the way we used because now we have a means to find the area of the larger since we know the area of the smaller.

Area exists in a squared-to-squared relationship of the perimeter which is one-to-one.  If the perimeter ratio is 1:3, then the area relationship is

\frac{s}{l}:\frac{1^2}{3^2} which is, simplified:

\frac{s}{l}:\frac{1}{9}

Since we know the area for the smaller, we can sub it into a proportion and cross multiply to solve for the area of the larger.

\frac{s}{l} :\frac{1}{9} =\frac{110.11}{x}

A of the larger is 990.99 units squared

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lapo4ka [179]

Answer: c

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