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Yuri [45]
3 years ago
13

What is 18/42 in simplest form

Mathematics
2 answers:
nirvana33 [79]3 years ago
8 0
\frac{18}{42} \\ \\ GCF = 6 \\ \\ 18 \div 6 = 3 \\ \\ 42 \div 6 = 7 \\ \\  \frac{3}{7} \\ \\ Answer: \fbox {3/7} \ or \ \fbox {0.4286}
kodGreya [7K]3 years ago
7 0
Divide.

18/6 = 3

42/6 = 7

3/7 , now we can't make this any smaller.

Answer: 3/7
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saw5 [17]

The answer you want is going to be A.

Hope it helps.


3 0
3 years ago
Subtract.(x + 1) − (−2x − 5) A) 6 − x
Inga [223]
Your answer would be D) 3x + 6
This is because, when you subtract the like terms, you get x - -2x, which is 3x, and 1 - -5, which is 6.

I hope this helps!
6 0
4 years ago
Read 2 more answers
A certain test preparation course is designed to help students improve their scores on the GMAT exam. A mock exam is given at th
Bogdan [553]

Answer:

95% confidence interval for the average net change is between a lower limit of 11.709 and an upper limit of 30.921.

The critical value that should be used in constructing the confidence interval is 4.303.

Step-by-step explanation:

Confidence interval is given as mean +/- margin of error (E)

mean = (17+20+26)/3 = 63/3 = 21

sd = sqrt[((17-21)^2 + (20-21)^2 + (26-21)^2) ÷ 3] = sqrt(42÷3) = sqrt(14) = 3.74

n = 3

degree of freedom = n-1 = 3-1 = 2

confidence level (C) = 95% = 0.95

significance level = 1 - C = 1 - 0.95 = 0.05 = 5%

critical value (t) corresponding to 2 degrees of freedom and 5% significance level is 4.303.

The critical value is 4.303

E = t×sd/√n = 4.303×3.74/√3 = 9.291

Lower limit of mean = mean - E = 21 - 9.291 = 11.709

Upper limit of mean = mean + E = 21 + 9.291 = 30.291

95% confidence interval is (11.709, 30.391)

8 0
3 years ago
The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp
ale4655 [162]

Answer:

6.26-2.01\frac{2.47}{\sqrt{50}}=5.56    

6.26+2.01\frac{2.47}{\sqrt{50}}=6.96    

So on this case the 95% confidence interval would be given by (5.56;6.96)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=6.26

The sample deviation calculated s=2.47

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=50-1=49

Assuming a Confidence of 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,49)".And we see that t_{\alpha/2}=2.01

Now we have everything in order to replace into formula (1):

6.26-2.01\frac{2.47}{\sqrt{50}}=5.56    

6.26+2.01\frac{2.47}{\sqrt{50}}=6.96    

So on this case the 95% confidence interval would be given by (5.56;6.96)    

6 0
3 years ago
If 45/60 is equivalent to 3/x, find the value of x
vladimir1956 [14]
X = 4
EXPLANATION:

45/60 can be simplified by dividing both 45 and 60 by the same number.

We already know the numerator is 3.

so we have to do the equation 45 divided by 3. which is 15.

so now we do 60 divided by 15 to find x.

So x = 4





6 0
3 years ago
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