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2 years ago

Please i need the step-by-step solution please thank you

Mathematics

2 answers:

nekit [7.7K]2 years ago

4 0

Answer:

6. option d

7.option c

Step-by-step explanation:

..........

Sergio [31]2 years ago

3 0

Answer:

Question 6: -8

Question 7: C

Step-by-step explanation:

Question 6:

The reason question 6 is -8 is because of the distance in between each number, e.g -7 and -15. This is not to be confused with + 8 each time that would make the sequence 9, 18, 27.

Question 7:

The way we solve this question is using the nth term rule, whatever is before the n is the times tables we follow. So if it is 2n the sequence would be 2, 4, 6, 8 etc. However when we add something like the -2 we do the 2 times tables but this time we -2 for each one. Example: 2 - 2 = 0 so the first number of the sequence is 0, Example 2: 4-2 = 2 so the second number of the sequence is 2.

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What's two thirds of a straight line?

Komok [63]

Well if the straight line is equal to 1 then your answer is 2/3 but if the straight line is not equal to 1 you need to know what it is equal to or you could use the equation y = (2/3)x
"x" would be the length of the straight line and "y" would be two-thirds of it

6 0

3 years ago

A blue die and a red die are thrown. B is the event that the blue comes up with a 6. E is the event that both dice come up even.

iVinArrow [24]

Answer:

Size of |E n B| = 2

Size of |B| = 1

Step-by-step explanation:

I'll assume both die are 6 sides

Given

Blue die and Red Die

Required

Sizes of sets

- $|E\ n\ B|$

- $|B|$

The question stated the following;

B = Event that blue die comes up with 6

E = Event that both dice come even

So first; we'll list out the sample space of both events

$B = \{6\}$

$E = \{2,4,6\}$

Calculating the size of |E n B|

$|E n B| = \{2,4,6\}\ n\ \{6\}$

$|E n B| = \{2,4,6\}$

The size = 3 because it contains 3 possible outcomes

Calculating the size of |B|

$B = \{6\}$

The size = 1 because it contains 1 possible outcome

8 0

2 years ago

How to solve logarithmic equations as such

Serga [27]

$\bf \textit{exponential form of a logarithm} \\\\ \log_a b=y \implies a^y= b\qquad\qquad a^y= b\implies \log_a b=y \\\\\\ \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} ~\hspace{7em} \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \log_2(x-1)=\log_8(x^3-2x^2-2x+5) \\\\\\ \log_2(x-1)=\log_{2^3}(x^3-2x^2-2x+5) \\\\\\ \log_{2^3}(x^3-2x^2-2x+5)=\log_2(x-1) \\\\\\ \stackrel{\textit{writing this in exponential notation}}{(2^3)^{\log_2(x-1)}=x^3-2x^2-2x+5}\implies (2)^{3\log_2(x-1)}=x^3-2x^2-2x+5$

$\bf (2)^{\log_2[(x-1)^3]}=x^3-2x^2-2x+5\implies \stackrel{\textit{using the cancellation rule}}{(x-1)^3=x^3-2x^2-2x+5} \\\\\\ \stackrel{\textit{expanding the left-side}}{x^3-3x^2+3x-1}=x^3-2x^2-2x+5\implies 0=x^2-5x+6 \\\\\\ 0=(x-3)(x-2)\implies x= \begin{cases} 3\\ 2 \end{cases}$

5 0

2 years ago

The answer because I hate homework it's to hard

Charra [1.4K]

The answer to what?

6 0

2 years ago

Can Someone come help me out here plzzz ..hurry uppp thxxx

WITCHER [35]

Answer:

It’s the last one

Step-by-step explanation:

You can see on the graph

6 0

2 years ago

Please i need the step-by-step solution please thank you ​

Please i need the step-by-step solution please thank you