Between the probability of union and intersection, it's not clear what you're supposed to compute. (I would guess it's the probability of union.) But we do know that
For parts (a) and (b), you're given everything you need to determine
.
For part (c), if
and
are mutually exclusive, then
, so
. If the given probability is
, then you can find
. But if this given probability is for the intersection, finding
is impossible.
For part (d), if
and
are independent, then
.
Answer:
Step 2
Step-by-step explanation:
Meredith made a fatal mistake or error in step 2;
Any quadratic problem will always have two solutions. Therefore since, we only have one solution here, it is wrong. The mistake was incurred in step 2;
From the given problem ;
<u> Wrong right</u>
2(x + 4)² = 242
(x + 4)² = 121 Step 1
x+4=11 Step 2 x + 4 = ± 11
x = 7 Step 3 x + 4 = 11 or x + 4 = -11
x = 11- 4 or x = -11 - 4
x = 7 or -15
15.48 + 5.16 = p because you have to do the reverse. to find "p" you have to add the amount you subtracted.
Use KMF (Keep multiply flip)
keep the first fraction as it is
change sign to multiplication
flip numerator and denominator of last fraction
then finish
Answer:
m^2 + 2n-17
Step-by-step explanation:
sorry is it too late
