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podryga [215]
3 years ago
11

Peter's salary is twice Anne's salary and half of David's salary. Then the average salary of Anne and David is _ of Peter's sala

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Mathematics
1 answer:
satela [25.4K]3 years ago
6 0
<h3><u>Answer:</u></h3>

Average of salary of Anne and David is 1.25 of Peter's Salary

<h3><u>Explanation:</u></h3>

In the question, relations between salaries of Peter, Anne, and David is given. From the given relations, we need to make few equations and calculate the average of Anne and David in terms of Peter's Salary.

Let us assume Peter's Salary as P.

Then we can calculate Anne's salary A = \frac{P}{2}.

Also David's salary = D = 2 \times P

Average of Anne's and David's salary = \frac{A+D}{2}

Average of Anne's and David's salary  = \frac{\frac{P}{2} + 2 \times P}{2}

Average of Anne's and David's salary  = \frac{5 \times P}{4}

Average = 1.25 \times P

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Let's solve this expression and then see which of the options is the correct one.

The first step to solve this is that we need for the two sides of the equation to have the same base. (the number 5 on the left side is the base, so we need to also have a 5 as the base on the right side).

We do this by noting that:

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We know that 25 is equal to 5 squared (because 5x5 is 25)

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Since we have the same base on both sides (5), we follow the rule:

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