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creativ13 [48]
3 years ago
13

Please show working for these 2 questions.

Mathematics
1 answer:
earnstyle [38]3 years ago
5 0
Question 6a:
Volume of the sand = 1/3π(10)²(25) = 2618 cm³

Answer: 2618 cm³

Question 6b:
 2618 cm³ = 1 hour
 2618 cm³ = 60 mins
 2618 cm³ = 3600 seconds
0.73 cm³ = 1 second

Answer: 0.73 cm³/s

Question 7a:
Volume = (1 x 10 x 10) + 1/2(1 + 2) x 10 x 10 = 100 + 150 = 250 m³

Answer: 250 m³

Question 7b:
250 m³ = 250 kl
1 kl = $1.98
250kl = $1.98 x 250 = $487.50

Answer:  $487.50
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A plane flies 640 mi with the wind in the same time that it takes to fly 440 mi against the wind. If this plane flies at the rat
777dan777 [17]

Answer:

what that this answer ⁉️

6 0
3 years ago
Find the common factor and rewrite. Type your answer in the box. Do not use any spaces.
finlep [7]

Common factor is 4X

Rewriting the term we get: 4X(Y + 2Z)

Step-by-step explanation:

We need to find the common factor of the expression: 4XY + 8XZ

A common factor is the term that is common in all the terms of the expression.

In the given expression the common factor is: 4X because it is common in both terms

4XY + 8XZ

=4X(Y + 2Z)

So, Common factor is 4X

Rewriting the term we get: 4X(Y + 2Z)

Keywords: Factors

Learn more about factors at:

  • brainly.com/question/10771256
  • brainly.com/question/1414350
  • brainly.com/question/2568692

#learnwithBrainly

3 0
3 years ago
It cost Hudson $28.20 to send 188 text messages. How much would it cost to send 63 text messages? Good luck!
frosja888 [35]

Answer:

$9.45

Step-by-step explanation:

1.  First, you want to figure out how much one text message costs.  To do this, divide the dollar amount (28.20) by the number of text messages (188).  You get 0.15, or $0.15 per text message.

2. Using this $0.15 per text message, you can calculate how much 63 text messages costs.  You simply multiply $0.15 by 63 to get $9.45, which is your answer.

Hope this helps! :)

3 0
3 years ago
1/3 1/4 3/8 7/24 5/12 which is the biggest
Sati [7]

Answer: 5/12

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
a. Among a shipment of 5,000 tires, 1,000 are slightly blemished. If one purchases 10 of these tires, what is the probability th
hodyreva [135]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

3 or less than 3 tires among the 10 tires should be blemished.

There are some possibilities.

1000 tires are blemished, (5000 - 1000) = 4000 tires are not blemished.

From the 5000 tires, 10 tires can be chosen in ^{5000}C_{10} ways.

Possibility 1: <u>3 tires are blemished.</u>

Total 10 tires can be chosen with 3 blemished tires in ^{1000}C_3 \times {4000}C_7 ways.

Possibility 2:  <u>2 tires are blemished.</u>

Total 10 tires can be chosen with 2 blemished tires in ^{1000}C_2 \times ^{4000}C_8  ways.

Possibility 3: <u>1 tires are blemished.</u>

Total 10 tires can be chosen with 1 blemished tires in ^{1000}C_1 \times^{4000}C_9 ways.

Possibility 4:  <u>No tires are blemished.</u>

Total 10 tires can be chosen with no blemished tires in ^{1000}C_0 \times^{4000}C_{10} ways.

Hence, the required probability is \frac{^{1000}C_1 \times^{4000}C_9 + ^{1000}C_0 \times^{4000}C_{10} + ^{1000}C_2 \times^{4000}C_8 + ^{1000}C_3 \times^{4000}C_7}{^{5000}C_{10} }.

6 0
3 years ago
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