All categories

3 years ago

Please show working for these 2 questions.

Mathematics

1 answer:

earnstyle [38]3 years ago

5 0

Question 6a:
Volume of the sand = 1/3π(10)²(25) = 2618 cm³

Answer: 2618 cm³

Question 6b:
2618 cm³ = 1 hour
2618 cm³ = 60 mins
2618 cm³ = 3600 seconds
0.73 cm³ = 1 second

Answer: 0.73 cm³/s

Question 7a:
Volume = (1 x 10 x 10) + 1/2(1 + 2) x 10 x 10 = 100 + 150 = 250 m³

Answer: 250 m³

Question 7b:
250 m³ = 250 kl
1 kl = $1.98
250kl = $1.98 x 250 = $487.50

Answer: $487.50

You might be interested in

A plane flies 640 mi with the wind in the same time that it takes to fly 440 mi against the wind. If this plane flies at the rat

777dan777 [17]

Answer:

what that this answer ⁉️

6 0

3 years ago

Find the common factor and rewrite. Type your answer in the box. Do not use any spaces.

finlep [7]

Common factor is 4X

Rewriting the term we get: $4X(Y + 2Z)$

Step-by-step explanation:

We need to find the common factor of the expression: $4XY + 8XZ$

A common factor is the term that is common in all the terms of the expression.

In the given expression the common factor is: 4X because it is common in both terms

$4XY + 8XZ$

$=4X(Y + 2Z)$

So, Common factor is 4X

Rewriting the term we get: $4X(Y + 2Z)$

Keywords: Factors

Learn more about factors at:

#learnwithBrainly

3 0

3 years ago

It cost Hudson $28.20 to send 188 text messages. How much would it cost to send 63 text messages? Good luck!

frosja888 [35]

Answer:

$9.45

Step-by-step explanation:

1. First, you want to figure out how much one text message costs. To do this, divide the dollar amount (28.20) by the number of text messages (188). You get 0.15, or $0.15 per text message.

2. Using this $0.15 per text message, you can calculate how much 63 text messages costs. You simply multiply $0.15 by 63 to get $9.45, which is your answer.

Hope this helps! :)

3 0

3 years ago

1/3 1/4 3/8 7/24 5/12 which is the biggest

Sati [7]

Answer: 5/12

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

a. Among a shipment of 5,000 tires, 1,000 are slightly blemished. If one purchases 10 of these tires, what is the probability th

hodyreva [135]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

3 or less than 3 tires among the 10 tires should be blemished.

There are some possibilities.

1000 tires are blemished, (5000 - 1000) = 4000 tires are not blemished.

From the 5000 tires, 10 tires can be chosen in $^{5000}C_{10}$ ways.

Possibility 1: <u>3 tires are blemished.</u>

Total 10 tires can be chosen with 3 blemished tires in $^{1000}C_3 \times {4000}C_7$ ways.

Possibility 2: <u>2 tires are blemished.</u>

Total 10 tires can be chosen with 2 blemished tires in $^{1000}C_2 \times ^{4000}C_8$ ways.

Possibility 3: <u>1 tires are blemished.</u>

Total 10 tires can be chosen with 1 blemished tires in $^{1000}C_1 \times^{4000}C_9$ ways.

Possibility 4: <u>No tires are blemished.</u>

Total 10 tires can be chosen with no blemished tires in $^{1000}C_0 \times^{4000}C_{10}$ ways.

Hence, the required probability is $\frac{^{1000}C_1 \times^{4000}C_9 + ^{1000}C_0 \times^{4000}C_{10} + ^{1000}C_2 \times^{4000}C_8 + ^{1000}C_3 \times^{4000}C_7}{^{5000}C_{10} }$ .

6 0

3 years ago