She invested $11,250 in the stock, $3,750 in the CD and $12,000 in the bond fund.
<h3><u>Distributions</u></h3>
Given that Sylvia invested a total of $27,000, and she invested part of the money in a certificate of deposit (CD) that earns 3% simple interest per year, she invested in a stock that returns the equivalent of 7% simple interest, and she invested in a bond fund that returns 2%, and she invested three times as much in the stock as she did in the CD, and earned a total of $1140 at the end of 1 yr, to determine how much principal did she put in each investment, the following calculation must be made:
- 9000 x 0.07 + 3000 x 0.03 + 15000 x 0.02 = 630 + 90 + 300 = 1020
- 9900 x 0.07 + 3300 x 0.03 + 13800 x 0.02 = 693 + 99 + 276 = 1068
- 12,000 x 0.07 + 4,000 x 0.03 + 11,000 x 0.02 = 840 + 120 + 220 = 1,180
- 11400 x 0.07 + 3800 x 0.03 + 11800 x 0.02 = 798 + 114 + 236 = 1148
- 10800 x 0.07 + 3600 x 0.03 + 12600 x 0.02 = 756 + 108 + 252 = 1116
- 11160 x 0.07 + 3720 x 0.03 + 12120 x 0.02 = 781.2 + 111.6 + 242.4 = 1135.2
- 11190 x 0.07 + 3730 x 0.03 + 12080 x 0.02 = 783.3 + 111.9 + 241.6 = 1136.8
- 11250 x 0.07 + 3750 x 0.03 + 12000 x 0.02 = 787.5 + 112.5 + 240 = 1140
Therefore, she invested $11,250 in the stock, $3,750 in the CD and $12,000 in the bond fund.
Learn more about distribution in brainly.com/question/10250387
Answer:
80
Step-by-step explanation:
Let's write out the equation:
8(20+80/2)/[(54/9+14)/4]
For the first part we get 8(100/2)
Then 50x8
Then 400
For the second part we have (6+14)/4 as we divide 54 by 9. PEMDAS
Then 20/4
Then 5
So our final answer is 400/5 which is 80.
Hope this helps!
The diameter is 48 feet. The radius is half of the diameter, so it is 24 feet. The area can be found using the formula pi r ^ 2. So, the area is 576 pi
Answer:
Second class have higher marks and greater spread.
Step-by-step explanation:
First box plot represents class first. From the first box plot, we get
Second box plot represents class second. From the second box plot, we get
First class has greater minimum value, first quartile of both classes are same, second class has greater median, first class has greater third quartile and first class has greater maximum value. It means second class have higher marks but class first have less variation.
Second class has greater range and greater inter quartile range. It means data of second class has greater spread.
Therefore, second class have higher marks and greater spread.
Answer: (f•g)(x)=2x²+12x
Step-by-step explanation:
(f•g)(x) is the same as saying f(x)•g(x). Since we have f(x) and g(x), we can just multiply them together.
(f•g)(x)=2x(x+6) [distribute by FOIL]
(f•g)(x)=2x²+12x
Now, we know that (f•g)(x)=2x²+12x.