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ladessa [460]
3 years ago
9

What is the equation of the line that passes through (0, 3) and (7, 0)?

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
5 0
The answer should be (C):y=(-3/7)x+3 because:

 if you use the slope formula: (Y2-Y1)/(X2-X1) it would look like this:

(0-3)/(7-0) and the slope of the line would be -3/7

then using the slope you just found, plug it into the y=mx+b equation along with one set of coordinates to find b (the y-intercept):

y=mx+b
0=(-3/7)(7)+b
b=3

SO, overall if you put the slope (m) and the y-intercept (b) that you found together, you get the line formula of y=(-3/7)+3 

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Hello!

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There is also an exponent of '6' outside. According to exponential properties, when an exponent is within an exponent, you multiply them together. Therefore:

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3 years ago
The sum of x and 6.5 is 11.9. Find<br> he value of x.
pashok25 [27]

Answer:

5.4

Step-by-step explanation:

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Therefore x is 5.4 :)

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brilliants [131]
First set up a proportion because they are similar triangles:
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4 0
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On Naomi's cell phone plan, the amount she pays each month for international text messages is proportional to the number of inte
Lostsunrise [7]

A) The constant of proportionality in this proportional relationship is k = \frac{y}{x}

B) The equation to represent this proportional relationship is y = 0.2x

<h3><u>Solution:</u></h3>

Given that,

The amount Naomi pays each month for international text messages is proportional to the number of international texts she sends that month

Therefore,

This is a direct variation proportion

\text{ amount Naomi pays each month } \propto \text{ number of international texts she sends that month}

Let "y" be the amount that Naomi pays each month

Let "x" be the number of international texts she sends that month

Therefore,

y \propto x

y = kx -------- eqn 1

Where, "k" is the constant of proportionality

Thus the constant of proportionality in this proportional relationship is:

k = \frac{y}{x}

<em><u>Last month, she paid $3.20 for 16 international texts</u></em>

Therefore,

y = 3.20

x = 16

Thus from eqn 1,

3.20 = k \times 16\\\\k = \frac{3.20}{16}\\\\k = 0.2

Substitute k = 0.2 in eqn 1

y = 0.2x

The equation would then be y = 0.2x

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