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geniusboy [140]
3 years ago
15

Must be added to 14056 to result in a sum of 38,773?

Mathematics
1 answer:
sweet [91]3 years ago
4 0
38773 - 14056 = 24717
24717 + 14056 = 38773
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The functions f(x) and g(x) are shown.
erastova [34]

The function f(x) takes on the value 2 when x =  -7 and x = -3, and thus the corresponding points are (-7,2) and (-3,2).

The points where g(x) = 0 are called "roots" or "solutions," and is (3,0).

f(x) > g(x)  on the approx. interval (-9, -3/4).

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JUST HELP ME! PLEASE!!..0o0<br><br>Applying the Pythagorean theorem, solve this triangle.​
Inessa [10]
<h3>Answer:    <u>100 ft</u>  is the hypotenuse</h3>

===================================================

Work Shown:

a = 60 and b = 80 are the two known sides

c  is the unknown hypotenuse

Applying the pythagorean theorem gets us...

a^2 + b^2 = c^2

60^2 + 80^2 = c^2

3600 + 6400 = c^2

10,000 = c^2

c^2 = 10,000

c = sqrt(10,000)

c = 100

A quick way to see that 100 ft is the missing side is to note that a 6,8,10 right triangle scales up to 60,80,100 after multiplying all three sides by 10.

Or you could start with a 3,4,5 right triangle and multiply all three sides by 20.

4 0
3 years ago
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What is the measure of one interior angle of a polygon that has 50 sides
pashok25 [27]

Answer: 172.8°

Step-by-step explanation:

For a regular polynomial of N sides, the sum of all interior angles must be equal to:

Sum = (N - 2)*180°.

In this case we have N = 50

Then:

Sum = (50 - 2)*180° = 48*180°

Now, if all the 50 interior angles have the same measure, then the measure of each one will be equal to the quotient between the sum and the number of sides, this is:

Sum/50 = (48/50)*180° = 172.8°

Then the interior angles of a regular polygon of 50 sides is 172.8°

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What is the area of the right triangle ABC, given a(1,4), B(3,2), and C(-1,-2)
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Answer:

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Step-by-step explanation:

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For each of the following functions, determine if they are injective. Also determine if theyare surjective. Also determine if th
timurjin [86]

Answer:

Check below

Step-by-step explanation:

1. Definition for intervals

(a,b)=\left \{ x\in\Re : a

2. Functions

1) \Re \rightarrow \Re \\ f(x)=x

Let's perform graph tests.

That's an one to one, injective function. Look how any horizontal line touches that only once. Also, It's a surjective and a bijective one.

2)\Re\geq0\rightarrow\Re , f(x)=x+1\\

Injective, surjective and bijective.

Injective: a horizontal line crosses the graph in one point.

3)f:\Re\geq 0\rightarrow\Re, f(x) = cos(x)

The cosine function is not injective, bijective nor surjective.

4)f:\Re\rightarrow\Re \:f(x)=ex

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5)  Quite unclear format

6) \:f:\Re\rightarrow(0,\infty), f(x) =ex

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10) f:\Re\geq 0\rightarrow [-1,1], f(x)= cos(x)\\-1=cos(x) \therefore x=\pi,3\pi,5\pi,etc.

Surjective.

11.f:R\geq 0[-1,1], f(x) = 0\\

Surjective

12.f: US Citizens→Z, f(x) = the SSN of x.

General function

13.f: US Zip Codes→US States, f(x) = The state that x belongs to.

Surjective

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